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Grace [21]
3 years ago
7

I don't understand the question ... find an equation for the line with an x intercept of 4 and a y intercept of -2

Mathematics
2 answers:
IceJOKER [234]3 years ago
4 0
The answer is y=1/2x -2

-In order to find this, you need to find the slope first.
-Since the x-intercept is (4,0) and the y-intercept is (0,-2), we can use (y-y1)/(x-x1).
-So, (0 - -2)/(4 - 0) = 2/4 = 1/2 (this is the slope)
-Using y=mx+b, where m= the slope and b=the y-intercept, plug in 1/2 for m and -2 for b
-Now the equation is y=1/2x -2
____ [38]3 years ago
4 0


1. first find the slope from the two points (4,0) and (0,-2)

    the equation is  y2 -y1/ x2 - x1

2. From doing that you will get a slope of 1/2

3. Since we need a y intercept of -2, when you plug in x to the equation the y must equal -2

   the only equation that fits those needs is y = 1/2x - 2

4. You can check by plugging in x as 4(which should give you y = 0), or plug in x as 0(which should give you y = -2
 
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2 years ago
Write the slope-intercept form of the equation for the line.
Fantom [35]
Well, let's take a peek at the graph of that line, hmmm let's pick two points, heck, those tow on the extremes anyway, and those are (-5,2) and (5,-1), alrite.. now, let's do some checking on that.

\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%   (a,b)
&({{ -5}}\quad ,&{{ 2}})\quad 
%   (c,d)
&({{ 5}}\quad ,&{{ -1}})
\end{array}
\\\\\\
% slope  = m
slope = {{ m}}= \cfrac{rise}{run} \implies 
\cfrac{{{ y_2}}-{{ y_1}}}{{{ x_2}}-{{ x_1}}}\implies \cfrac{-1-2}{5-(-5)}\implies \cfrac{-1-2}{5+5}
\\\\\\
\cfrac{-3}{10}

\bf \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-2=-\cfrac{3}{10}[x-(-5)]
\\\\\\
y-2=-\cfrac{3}{10}(x+5)\implies y-2=-\cfrac{3}{10}x-\cfrac{3}{2}\implies y=-\cfrac{3}{10}x-\cfrac{3}{2}+2
\\\\\\
y=-\cfrac{3}{10}x+\cfrac{1}{2}
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