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skad [1K]
3 years ago
10

If Jane's shirt cost 20$, but she has a 15% off coupon, what is her cost before tax

Mathematics
1 answer:
Readme [11.4K]3 years ago
7 0

Answer:

17

Step-by-step explanation:

The discount on the shirt is 15%

Discount = price* discount rate

               = 20 * 15%

               = 20 * .15

                =3

The new price is the previous price minus the discount

new price = 20-3

new price = 17

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A tortoise makes a journey in two parts; it can either walk at 4cm/s or crawl at 3cm/s.
Semenov [28]

Answer:

y = 240 cm crawl

x = 120 cm walking

Step-by-step explanation:

Logic....

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3 years ago
10.222 in a fraction
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5111/500 or 10 111/500
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17. Which of the following measures can be calculated for qualitative data? a. Mean b. Median c. Mode d. All of these
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Step-by-step explanation:

Qualitative data applies to observable data such as reoccurring patterns (mode)

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6 0
3 years ago
Please help fast!! Katrina has $3.60 worth of nickels and dimes. She has 46 coins in total. How many nickels and dimes does she
Igoryamba

Answer:

20 nickels and 26 dimes

Step-by-step explanation:

  • She has $3.60 in nickels and dimes
  • a nickel is $0.05 and a dime is $0.10
  • let n be the number of nickels and d be the number of dimes
  • thus the first equation is 3.6 = 0.05n +0.1d
  • If she has 46 coins then n + d = 46
  • then n = 46 - d
  • sub n = 46 - d into 3.6 = 0.05n +0.1d
  • 3.6 = 0.05(46 - d) + 0.1d
  • 3.6 = 2.3 -0.05d+0.1d
  • 1.3 = 0.05d
  • 26 = d
  • sub d = 26 into n+d=46
  • n+26=46
  • n=20
  • Check by subbing n=20 and d=26 into 0.05n +0.1d
  • 0.05(20) +0.1(26)
  • 1+2.6 = 3.6
6 0
3 years ago
Write an equation for an exponential growth function where the initial population is 74 and the population quadruples during eac
Liono4ka [1.6K]
If the population quadruples every period say hour, that means the "rate of growth" is 300%, so whatever the current amount, increased by 3 times as much is 4 times the current amount, or a quadrupled amount.

\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &74\\
r=rate\to 300\%\to \frac{300}{100}\to &3.00\\
t=\textit{elapsed time}\\
\end{cases}
\\\\\\
A=74(1+3)^t\implies A=74(4)^t
6 0
3 years ago
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