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Papessa [141]
3 years ago
14

PLEASE HELP!!!! WILL GIVE BRAINLEST

Mathematics
1 answer:
tiny-mole [99]3 years ago
4 0

Answer:

31

Step-by-step explanation:

Since the two sides are equal, the two angles are equal

8x-1 = 5x+11

Subtract 5x from each side

8x-5x -1 = 5x-5x+11

3x-1 =11

Add 1 to each side

3x-1+1 =11+1

3x =12

Divide by 3

3x/3 =12/3

x =4

Now we can find WZY

5x+11

5(4)+11

20+11

31

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the graph linear function f passes through the point (1,-9) and a slope.of -3. what is the zero of f?
gizmo_the_mogwai [7]

Answer:

m = 5  ,  ( 1 , 1 ) − 3  ,  ( 1 , 3 ) 3  ,  (2 ,9 )

Step-by-step explanation:

5 0
2 years ago
[HELP] Are the diagonals of an isosceles trapezoid congruent?
erastovalidia [21]
Yes.

the properties of an isosceles trapezoid are:
- the bases are parallel 
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3 0
3 years ago
A produce supplier ships boxes of produce to individual customers. The distribution of weights of shipped boxes is approximately
schepotkina [342]

Answer:

0.67(4)+ 36

Option D

Step-by-step explanation:

Given that a producer ships boxes of produce to individual customers.(say x)

X is a normal random variable with mean = 36 and std dev  =4 lbs

By definition of std normal variate we know that

\frac{x-36}{4} is N(0,1)

75th percentile of std normal distribution is

0.675

Hence corresponding x would be

36+0.675(4)

Option D matches with this value

Hence answer is option D

0.67(4)+ 36

5 0
3 years ago
Read 2 more answers
theo made sails for a model boat.He cut along the diagonal of a rectangular piece of cloth to make two sails as shown below.What
schepotkina [342]
Given:

A rectangular piece of cloth (dimensions):

L = length of the rectangle
W = width of the rectangle

The area of the rectangle is:

A = L x W

If the cloth is cut along the diagonal, the area of one sail will be half the area of the rectangle:

 A (one sail) = 1/2 (L x W) <span />
5 0
2 years ago
Solve the inequality
GenaCL600 [577]
-1 < c + 2 < 3....subtract 2 from all sections
-1 - 2 < c + 2 - 2 < 3 - 2...simplify
-3 < c < 1
==============================
32 > 16 - 4g > 12....subtract 16 from all sections
32 - 16 > 16 - 16 - 4g > 12 - 16....simplify
16 > -4g > -4 ...now divide all sections by -4, and change inequality signs
16/-4 < (-4/-4)g < -4/-4...simplify
-4 < g < 1
============================
6y + 1 > = 10
6y > = 10 - 1
6y > = 9
y > = 9/6 which reduces to 3/2 or 1 1/2

-3/2y > = 9 ....multiply both sides by -2/3, cancelling the -3/2 on the left...and change the inequality sign
y < = 9 * -2/3
y < = -18/3 which reduces to - 6

so y > = 9/6(or 1 1/2) or y < = -6


3 0
3 years ago
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