Given the expression,

We will have to rationalize the denominator first. To rationalize the denominator we have to multiply the numerator and denominator both by the square root part of the denominator.
![[(8x-56x^2)(\sqrt{14x-2})]/[(\sqrt{14x-2})(\sqrt{14x-2})]](https://tex.z-dn.net/?f=%20%5B%288x-56x%5E2%29%28%5Csqrt%7B14x-2%7D%29%5D%2F%5B%28%5Csqrt%7B14x-2%7D%29%28%5Csqrt%7B14x-2%7D%29%5D%20)
If we have
, we will get
by multiplying them. And
.
So here in the problem, we will get,
![[(8x-56x^2)(\sqrt{14x-2})]/(14x-2)](https://tex.z-dn.net/?f=%20%5B%288x-56x%5E2%29%28%5Csqrt%7B14x-2%7D%29%5D%2F%2814x-2%29%20)
Now in the numerator we have
. We can check 8x is common there. we will take out -8x from it, we will get,


And in the denominator we have
. We can check 2 is common there. If we take out 2 from it we will get,

So we can write the expression as
![[(-8x)(7x-1)(\sqrt{14x-2})]/[2(7x-1)]](https://tex.z-dn.net/?f=%20%5B%28-8x%29%287x-1%29%28%5Csqrt%7B14x-2%7D%29%5D%2F%5B2%287x-1%29%5D%20)
is common to the numerator and denominator both, if we cancel it we will get,

We can divide -8 by the denominator, as -8 os divisible by 2. By dividing them we will get,


So we have got the required answer here.
The correct option is the last one.
Answer:
0.85
Step-by-step explanation:
P(E)+P(E')=1
SO, P(E')=1-P(E)
OR,P(E')=1-0.15
PLEASE MARK MY ANSWER AS BRAINLIEST.
= 0.85
The midpoint between these two would be -7, as you would add these two numbers, and then divide by two.
Hello!
Let's find the area and see!
A = s^2
A = 3^2
A = 6 ft^2
Now, if you double 3, you get 6. 3 × 2 = 6 Find the area:
A = 6^6
A = 36 ft^2
ANSWER:
No, the area will not be doubled. The area was 9 ft^2 when the sides were 3 feet long. If you double 9, you get 18, since 9 × 2 = 18.
36 is not the double of 9, so no, the area is not double.
Answer:
56 meters.
Step-by-step explanation:
Please find the attachment.
Let the leaning tower's be h meters tall, when it was originally built.
We can see from our attachment that the side with length 55.86 meters is hypotenuse and h is adjacent side for 4 degree angle.
Since we know that cosine relates the adjacent and hypotenuse of a right triangle.

Upon substituting our given values we will get,



Therefore, the leaning tower was approximately 56 meters, when it was originally built.