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2 years ago

!!50 POINTS!! Better Buy?

Mathematics

2 answers:

olchik [2.2K]2 years ago

7 0

Answer:

The best buy item is the Frito-Lay mi Variety Pack. Going for only 0.35 per item.

Step-by-step explanation:

All I did was the equations and then I compared the answer, the lowest answer is the best buy since it is the lowest price found.

Frito-Lay:

9.88/28 = 0.35

Unit rate is 35 cents

Pringles:

6.48/18 = 0.36

Unit rate is 36 cents
Pack of 18:

11.21/18 = 0.6

Unit rate is 60 cents

Pack of 24:

15.85/24 = 0.66

Unit rate is 66 cents

GC:

14.75/30 = 0.49

Unit rate is 49 cents

Sweet Treats:

10.75/25 = 0.43

Unit rate is 43 cents

Comparing all of this data, it can easily be seen that the Frito-Lay mi Variety Pack is the best deal you can find out of these 6 deals.

leonid [27]2 years ago

5 0

Answer: Frito Lay mi Variety Pack

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3 years ago

According to national data, 5.1% of burglaries are cleared with arrests. A new detective is assigned to six different burglaries

blagie [28]

Answer:

26.95% probability that at least one of them is cleared with an arrest

Step-by-step explanation:

For each burglary, there are only two possible outcomes. Either it is cleared, or it is not. The probability of a burglary being cleared is independent of other burglaries. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

5.1% of burglaries are cleared with arrests.

This means that $p = 0.051$

A new detective is assigned to six different burglaries.

This means that $n = 6$

What is the probability that at least one of them is cleared with an arrest?

Either none are cleared, or at least one is. The sum of the probabilities of these events is 100% = 1. So

$P(X = 0) + P(X \geq 1) = 1$

We want $P(X \geq 1)$

Then

$P(X \geq 1) = 1 - P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{6,0}.(0.051)^{0}.(0.949)^{6} = 0.7305$

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.7305 = 0.2695$

26.95% probability that at least one of them is cleared with an arrest

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