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stich3 [128]
4 years ago
15

Is it true that 1 2/5 - 3/4 = 1/4 + 2/5? Prove your answer.

Mathematics
2 answers:
Harrizon [31]4 years ago
8 0

Answer: Yes, it's true.

Step-by-step explanation:

The first step is to convert the mixed number 1\frac{2}{5} to a fraction. The procedure for this is:

  1. Multiply the whole number 1 by the denominator 5.
  2. Add the product obtained and the numerator 2 (This will be the numerator of the fraction).
  3. The denominator does not change. It will be 5.

Then:

1\frac{2}{5}=\frac{(1)(5)+2}{5}=\frac{7}{5}

Rewrite the equation:

\frac{7}{5}-\frac{3}{4}=\frac{1}{4}+\frac{2}{5}

Notice that the denominators on the left side are 4 and 5 and the denominator on the right side are also 4 and 5.

Then, the Least Common Denominator (LCD) on both sides is:

5=5\\\\4=2*2=2^2

LCD=5*2^2=20

Now we can solve the subtraction on the left side of the equation and the addition on the righ side:

\frac{(7*4)-(3*5)}{20}=\frac{(1*5)+(2*4)}{20}\\\\\frac{13}{20}=\frac{13}{20}

Therefore:

1\frac{2}{5}-\frac{3}{4}=\frac{1}{4}+\frac{2}{5}  (IT'S TRUE)

stiv31 [10]4 years ago
7 0

Answer: I don't think so because 1 2/5-3/4 equals 13/20

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What are the domain and range of f(x) = 4* – 8?
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Answer:

domain: {x | x is a real number}

range: {y l y> -8}

Step-by-step explanation:

f(x) = 4x² – 8 is a parabola, a U shape.

Since the stretch factor, 4, is positive, it opens up, there it will have a minimum value, the lowest point in the parabola.

y > -8  because the minimum is -8.

Parabolas do not have restricted "x" values. "4" does not restrict x because it is the stretch factor, which determines how wide the parabola is.

Quadratic standard form:

f(x) = ax² + bx + c

"a" represents how wide the graph is. If it's negative it opens down, if it's positive it opens up.

"b", if written, tells you it is not centred on the y-axis. It is not written, so the vertex is on the y-axis.

"c" is the y-intercept. In this case, since b = 0, it is also the minimum value.

7 0
3 years ago
A rectangle is 5.1 cm wide and each diagonal is 9.3 cm long. What is the measure of the angle between a diagonal and the shorter
Anastasy [175]

Answer:

56.7°

Step-by-step explanation:

A rectangle is 5.1 cm wide and each diagonal is 9.3 cm long. What is the measure of the angle between a diagonal and the shorter side of the rectangle to the nearest tenth of a degree?

We solve this question using the Trigonometric function of Sine

From the question, we are told that:

A rectangle is 5.1 cm wide

and each diagonal is 9.3 cm long.

Since we have a diagonal, this means the shape is transformed to a triangle.

The width of the rectangle = Adjacent side of a triangle = 5.1cm

The diagonal of the rectangle = Hypotenuse = 9.3cm

Hence,

cosθ = Adjacent/Hypotenuse

cosθ = 5.1/9.3

cosθ = 0.5483870968

θ = arccos(0.5483870968)

θ = 56.743568714°

Approximately = 56.7°

The measure of the angle is 56.7°

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3 years ago
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kodGreya [7K]

Answer: If it has a negative sign then drag it to one that doesn't have one and vice-versa

Step-by-step explanation:

so 0.005 would be -0.005

8 0
3 years ago
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What's the sum of an infinite geometric series if the first term is 156 and the common ratio is 2∕3?
DENIUS [597]

Answer:

468

Step-by-step explanation:

Formula for infinite sum of geometric series is;

S_∞ = a1/(1 - r)

Where;

a1 is first term

r is common ratio

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Thus;

S_∞ = 156/(1 - ⅔)

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