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amm1812
3 years ago
5

The pyramid ABCDE has a square base. the pyramid is 20cm high and each sloping edge measures 30cm. calculate the length of the s

ides the base

Mathematics
1 answer:
Amanda [17]3 years ago
8 0

Answer:

44.8 cm

Step-by-step explanation:

Vertical height (h) = EM = 20 cm

Slant height (l) = 30 cm

This two heights form a right angle at the interception at the base. Thus, we have a right angle triangle.

The length of the sides of the base = 2 × the base of the right triangle

✔️Use Pythagorean theorem to find the base of the right triangle formed. Thus: c² = a² + b²

a = base of the triangle

b = h = 20 cm

c = l = 30 cm

Plug in the values

30² = a² + 20²

a² = 30² - 20²

a² = 500

a = √500

a = 22.4 cm

✔️length of the sides of the base = 2 × the base of the right triangle

= 2 × a

= 2 × 22.4

= 44.8 cm

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Answer:

Arc length MK = 15.45 units (nearest hundredth)

Arc measure = 58.24°

Step-by-step explanation:

Calculate the measure of the angle KLN (as this equals m∠KLM which is the measure of arc MK)

ΔKNL is a right triangle, so we can use the cos trig ratio to find ∠KLM:

\sf \cos(\theta)=\dfrac{A}{H}

where:

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Given:

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\implies \sf \cos(KLM)=\dfrac{8}{15.2}

\implies \sf \angle KLM=\cos^{-1}\left(\dfrac{8}{15.2}\right)

\implies \sf \angle KLM=58.24313614^{\circ}

Therefore, the measure of arc MK = 58.24° (nearest hundredth)

\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right) \quad \textsf{(where r is the radius and}\:\theta\:{\textsf{is the angle)}

Given:

  • r = 15.2
  • ∠KLM = 58.24313614°

\implies \textsf{Arc length MK}=2 \pi (15.2)\left(\dfrac{\sf \angle KLM}{360^{\circ}}\right)

\implies \textsf{Arc length MK}=\sf 15.45132428\:units

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