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3 years ago

What is 2,520 divided by 16?

Mathematics

2 answers:

oksano4ka [1.4K]3 years ago

6 0

Answer:

157.5

Step-by-step explanation:

maw [93]3 years ago

3 0

Answer:

157.5 is the answer

Step-by-step explanation:

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Which statement about the numbers 22.407 and 22.416 is true? 22.407 = 22.416 because the values of the 4 in the tenths places ar

lara [203]

Answer:

22.407 < 22.416 because the value of the 0 in the hundredths place is less than the value of the 1.

SHOW ANSWER

Step-by-step explanation:

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2 years ago

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Aaron run 6 miles each day for three days. How many miles does she run it all? Write an addition and a multiplication sentence t

artcher [175]

6*3=18 miles in total

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3 years ago

Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca

Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

$\frac{dQ}{dt} = -rt$

Which has the following solution:

$Q(t) = Q(0)e^{-rt}$

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that $Q(6) = (1-0.03)Q(0) = 0.97Q(0)$ . We use this to find r.

$Q(t) = Q(0)e^{-rt}$

$0.97Q(0) = Q(0)e^{-6r}$

$e^{-6r} = 0.97$

$\ln{e^{-6r}} = \ln{0.97}$

$-6r = \ln{0.97}$

$r = -\frac{\ln{0.97}}{6}$

$r = 0.0051$

$Q(t) = Q(0)e^{-0.0051t}$

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

$Q(t) = Q(0)e^{-0.0051t}$

$0.5Q(0) = Q(0)e^{-0.0051t}$

$e^{-0.0051t} = 0.5$

$\ln{e^{-0.0051t}} = \ln{0.5}$

$-0.0051t = \ln{0.5}$

$t = -\frac{\ln{0.5}}{0.0051}$

$t = 135.9$

The half-life of the radioactive substance is 135.9 hours.

6 0

2 years ago

Write an equation of the line that has a slope of 3 and contains the point (2,5) in point-slope for

enot [183]

The equation would be y=3x-1

Point Slope Formula:

y - y1 = m(x - x1)

y - 5 = 3(x-2)
y - 5 = 3x - 6
+ 5 + 5
--------------------
y = 3x - 1

8 0

3 years ago

Read 2 more answers

Quadrilateral OPQR is inscribed in circle N, as shown below. Which of the following could be used to calculate the measure of ∠P

Rama09 [41]

Answer:

$m \angle PQR=80^{\circ}$

Step-by-step explanation:

Missing figure drawn.

The measure of ∠PQR is found by the property of inscribed quadrilateral. In an inscribed quadrilateral the opposite angles are supplementary:

$\left\{\begin{matrix}\angle O+\angle Q=180^{\circ} & \\ \angle P +\angle R=180^{\circ} & \end{matrix}\right.$

$x+16+6x-4=180^{\circ}\\7x+12=180\\7x+12-12=180-12\\7x=168\\\frac{7x}{7}=\frac{168}{7}\\x=14\\\angle Q=6(14)-4\Rightarrow m\angle Q=84-4\Rightarrow Q=80^{\circ}$

4 0

3 years ago