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lana66690 [7]
3 years ago
12

What is the true solution to the logarithmic equation?log2 [log2(sqrt4x)]=1​

Mathematics
2 answers:
erastova [34]3 years ago
8 0

Answer:4

Step-by-step explanation:

log₂[log₂(√4x)] = 1

log₂2 =1

So we replace our 1 with log₂2

log₂[log₂(√4x)] = log₂2

log₂ on bothside will cancel each other.

We will be left with;

[log₂(√4x)] = 2

log = power of exponential

√4x = 2²

√4x = 4

Square bothside

(√4x)² = 4²

4X = 16

Divide bothside by 4

4x/4 = 16/4

x = 4

Deffense [45]3 years ago
6 0

Answer:

x=4

Step-by-step explanation:

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Answer:

see explanation

Step-by-step explanation:

By the rational root theorem, any rational roots of f(x) are expressible in the form

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The possibilities are ± 1, ± 2, ± 3, ± 6

Since the lead coefficient is 1 dividing by that number doesn't change a thing.

Thus the possible rational roots are

\frac{p}{q} = - 6, - 3, - 2, -1, 1, 2, 3, 6

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