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lana66690 [7]
4 years ago
12

What is the true solution to the logarithmic equation?log2 [log2(sqrt4x)]=1​

Mathematics
2 answers:
erastova [34]4 years ago
8 0

Answer:4

Step-by-step explanation:

log₂[log₂(√4x)] = 1

log₂2 =1

So we replace our 1 with log₂2

log₂[log₂(√4x)] = log₂2

log₂ on bothside will cancel each other.

We will be left with;

[log₂(√4x)] = 2

log = power of exponential

√4x = 2²

√4x = 4

Square bothside

(√4x)² = 4²

4X = 16

Divide bothside by 4

4x/4 = 16/4

x = 4

Deffense [45]4 years ago
6 0

Answer:

x=4

Step-by-step explanation:

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3 years ago
Suppose that $5500 is placed in an account that pays 2% interest compounded each year.
pogonyaev

Answer: After 1 year:    $5,610

After 2 years: $5,722.20

Step-by-step explanation: Use the formula for periodic compounding interest, which is

A = P(1 + r/n)^(nt), where A is the final amount, P is the initial deposit, r is the interest rate as a decimal, n is the number of times the interest is compounded per year, and t is how many years.

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