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lana66690 [7]
3 years ago
12

What is the true solution to the logarithmic equation?log2 [log2(sqrt4x)]=1​

Mathematics
2 answers:
erastova [34]3 years ago
8 0

Answer:4

Step-by-step explanation:

log₂[log₂(√4x)] = 1

log₂2 =1

So we replace our 1 with log₂2

log₂[log₂(√4x)] = log₂2

log₂ on bothside will cancel each other.

We will be left with;

[log₂(√4x)] = 2

log = power of exponential

√4x = 2²

√4x = 4

Square bothside

(√4x)² = 4²

4X = 16

Divide bothside by 4

4x/4 = 16/4

x = 4

Deffense [45]3 years ago
6 0

Answer:

x=4

Step-by-step explanation:

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400 reduced by 3 times my age is 163
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Linear equation topic. (Lisa is 5 years younger than his elder brother,Daniel.The product of their ages is 2/3 of their grandmot
alisha [4.7K]
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x(x - 5) = 2/3 × y
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x² - 5x = 36 years
x² - 5x - 36 = 0
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√∆ = √169 = 13
x\:  =  \:  \frac{ - b \:   \frac{ + }{ }   \:  \sqrt{ {b}^{2}  \:  -  \: 4ac} }{2a}
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You are choosing between two health clubs. Club A offers membership for a fee of $ 28 plus a monthly fee of $ 22. Club B offers
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Step-by-step explanation:

Let x denote the number of months then

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