What is the true solution to the logarithmic equation?log2 [log2(sqrt4x)]=1
2 answers:
Answer:4
Step-by-step explanation:
log₂[log₂(√4x)] = 1
log₂2 =1
So we replace our 1 with log₂2
log₂[log₂(√4x)] = log₂2
log₂ on bothside will cancel each other.
We will be left with;
[log₂(√4x)] = 2
log = power of exponential
√4x = 2²
√4x = 4
Square bothside
(√4x)² = 4²
4X = 16
Divide bothside by 4
4x/4 = 16/4
x = 4
Answer:
x=4
Step-by-step explanation:
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