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lana66690 [7]
3 years ago
12

What is the true solution to the logarithmic equation?log2 [log2(sqrt4x)]=1​

Mathematics
2 answers:
erastova [34]3 years ago
8 0

Answer:4

Step-by-step explanation:

log₂[log₂(√4x)] = 1

log₂2 =1

So we replace our 1 with log₂2

log₂[log₂(√4x)] = log₂2

log₂ on bothside will cancel each other.

We will be left with;

[log₂(√4x)] = 2

log = power of exponential

√4x = 2²

√4x = 4

Square bothside

(√4x)² = 4²

4X = 16

Divide bothside by 4

4x/4 = 16/4

x = 4

Deffense [45]3 years ago
6 0

Answer:

x=4

Step-by-step explanation:

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Answer:

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3 years ago
30 POINTS IF U CAN HELP PLEASE. in the figure below, a tangent and a secant are drawn to a circle from the exterior point E. Sup
dimulka [17.4K]

Answer:

19.5  = CD

Step-by-step explanation:

The square of the tangent = the the whole secant times the outside part of the secant.

EG²= (ED)(EC)

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169 = 26EC

169/26 = EC

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Now  ED = EC + CD

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2 years ago
Pleasee help me due at 11:59 pleaseeeeeeeee​
Debora [2.8K]

Answer:

36 3/4

Step-by-step explanation:

I understand now why it was wrong. I am so very sorry and I fixed the answer

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3 years ago
Can someone please help me solve this, thank you so much if u help!
malfutka [58]

Answer:

  68°

Step-by-step explanation:

The triangle containing the 79° angle is isosceles. That means the other base angle is also 79°. The central angle is ...

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Angle X is the other acute angle in right triangle VWX, so has measure ...

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_____

<em>Additional comment</em>

A tangent makes a right angle with the radius to the point of tangency. W is the point of tangency, so angle VWX is a right angle.

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