Consider ∆JWZ and ∆JKZ
WZ~KJ (given)
<u>/</u><u> </u><u>WZJ</u>~<u>/</u><u> </u>KJZ (given)
JZ~JZ (common)
Therefore,
∆JWZ~∆JKZ by SAS congruence rule.
JW~ZK by CPCT.
1. Find the greatest common factor (GCF)
What is the largest number that divides evenly into 4x^2, -16x^4, and 10x^5?
It is 2.
What is the highest degree of x that divides evenly into 4x^2, -16x^4, and 10x^5?
It is x^2.
Multiply the results above, the GCF = 2x^2
2. Factor out the GCF (Write the GCF first. Then, in parentheses, divide each term by the GCF.)
2x^2(4x^2/2x^2 + -16x^4/2x^2 + 10x^5/2x^2)
3. Simplify each term in parentheses
2x(2-8x^2+5x^3)
Have a nice day :D
Answer:
A. 27°
Step-by-step explanation:
Given that s is perpendicular to r, and <1 = 3x, <2 = 5x + 18, therefore:
m<1 + m<2 = 90°
3x + (5x + 18) = 90°
Solve for x using this equation
3x + 5x + 18 = 90
8x + 18 = 90
Subtract 18 from both sides
8x + 18 - 18 = 90 - 18
8x = 72
Divide both sides by 8
x = 9
Find m<1
m<1 = 3x
Plug in the value of x
m<1 = 3(9) = 27°
Answer:
When you do polygons on a coordinate grid, you will have points and then you connect them to form any type of polygon. There must be a total of 3 or more coordinate points.
Um this is a chemistry question, you should probably put it in the chemistry section.
