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m_a_m_a [10]
3 years ago
15

Someone knows this?? the answers choices are in the picture thank you​

Mathematics
1 answer:
jasenka [17]3 years ago
6 0

Answer:

mjnhbgv

Step-by-step explanation:

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Help with this question ??
NNADVOKAT [17]

Answer: 12 tables minimum, 15 max.

Step-by-step explanation:

If you substitute 14 in an inequality

200c + 500t >= 8800

200(14) + 500t and solve for t, you get t must be at least 12.

C +T cannot exceed 29

So figure 14 +12 =26 so they could sell up to 15 tables and not go over 29.

You will have to enter the t values 12,13,14,15

5 0
3 years ago
Help pls. I'm stuck I just need the answer
sukhopar [10]

Answer:

39 men, 13 women

Step-by-step explanation:

you're saying you just need the answer so i hope this works. good luck :)

8 0
3 years ago
a country radio asks every 5th caller what is their favorite type of music, is this biased or unbiased?
Natasha_Volkova [10]

Answer:

unbiased, I think

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What kind of triangle is this?
Sindrei [870]
Right angle
Te reason being is that it has a 90° corner.

Hoped this helped
3 0
3 years ago
Read 2 more answers
Find the times (to the nearest hundredth of a second) that the weight is halfway to its maximum negative position over the inter
hoa [83]

Answer:

0.20 and 0.36

Step-by-step explanation:

y(t) = 2 sin (4π t) + 5 cos (4π t)

We wish to convert this to:

y = A sin(ωt + φ)

We know that ω = 4π.  We also know the following:

5 = A sin φ

2 = A cos φ

Divide the first equation by the second equation:

5/2 = tan φ

φ = tan⁻¹(5/2)

Now, square the two equations and add them together.

5² + 2² = (A sin φ)² + (A cos φ)²

29 = A²

A = √29

The equation of the wave is therefore:

y = √29 sin(4π t + tan⁻¹(5/2))

The maximum negative position is -√29.  And half of that is -½√29.

-½√29 = √29 sin(4π t + tan⁻¹(5/2))

-½ = sin(4π t + tan⁻¹(5/2))

7π/6 + 2kπ or 11π/6 + 2kπ = 4π t + tan⁻¹(5/2)

7 + 12k or 11 + 12k = 24t + 6 tan⁻¹(5/2) / π

t = (7 + 12k − 6 tan⁻¹(5/2) / π) / 24 or (11 + 12k − 6 tan⁻¹(5/2) / π) / 24

Trying different integer values of k, we find there are two possible values for t between 0 and 0.5, both when k = 0.

t = (7 − 6 tan⁻¹(5/2) / π) / 24 or (11 − 6 tan⁻¹(5/2) / π) / 24

t ≈ 0.20 or 0.36

5 0
3 years ago
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