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4 years ago

Please show me how to do this!!

Mathematics

1 answer:

astra-53 [7]4 years ago

5 0

An x-intercept occurs where, in an ordered pair, the x-value is any number and the y-value is zero. This results in a point on the function lying exactly on the x-axis, hence why it's called an x-intercept.

Using your table, none of the x-values have a matching y-value that equals zero. So, it's safe to assume your answer is option D. None of those points cross the x-axis.

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Next week, Josephine wants: to spend the same total amount of time, but practice the same number of hours each of the 4 days. Ho

Contact [7]

Answer:

I got the same question on Khan Academy. I was going to ask that too but saw that you already did. Maybe try to point it out to someone else on Brainly. Sorry that I could not help.

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

PLEASE HELP I"M ON A TIME LIMT!!

NemiM [27]

Answer: C) 1560

Step-by-step explanation:

So the first part is splitting the rectangle from the triangle so the area for the rectangle is 1440 (40 x 36) and the area for the triangle is 120 ((6x40)/ 2)

when you add them up the equal 1560 (1440 + 120)

8 0

3 years ago

What number can be written as 40 plus 5 ?

Sergio [31]

40+5=45 is written in extended form so your answer is 45

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3 years ago

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It takes Ty 4 hours 30 minutes to read his favorite book, reading at a constant rate of 100 pages

AysviL [449]

Answer:

540 pages

Step-by-step explanation:

100 pages = 50 mins

??? pages = 270 mins (converted 4hrs 30 mins to minutes)

Now you could cross multiply to find what the number of pages are:

100 pages x 270 mins = 50 mins x ??? pages

27000 = 50 mins x ??? pages

27000/50 = ??? pages

540 = ??? pages

So there are 540 pages in his favourite book.

8 0

3 years ago

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

1 year ago