-4 4/5 ÷ 4 = -24/5 x 1/4 = -6/5 = -1 1/5
Answer:
notice what it says at the top got to you tube if you need help
Step-by-step explanation:
The cupons help get the thing for less.
the cost for each of jelly beans and each pound of trail mix is $2.5 and $1.75
<u>Step-by-step explanation:</u>
Given A store is having a sale on jelly beans and trail mix. For 3 pounds of jelly beans and 2 pounds of trail mix, the total cost is $11. For 5 pounds of jelly beans and 6 pounds of trail mix, the total cost is $23 . We have to find the cost for each pound of trail mix and each pound of jelly beans.
Let the cost of each pound of trail mix is $y.
and the cost of each pound of jelly beans is $x.
According to question,
For 3 pounds of jelly beans and 2 pounds of trail mix, the total cost is $11.
⇒ 
→ (1)
For 5 pounds of jelly beans and 6 pounds of trail mix, the total cost is $23
⇒ 
→ (2)
Solving (1) and (2), we get
3(1 equation)-(2 equation)=0
⇒
⇒
hence,
⇒
⇒
Putting in we get ;
⇒
⇒ 
⇒ 
⇒ 
Hence, the cost for each of jelly beans and each pound of trail mix is $2.5 and $1.75 .
Answer:
Any one of these three works:
plane MOU
plane MNU
plane NOU
Step-by-step explanation:
A plane can be named by a single letter, such as L in this problem, or by any three non-collinear points that lie on the plane. Non-collinear points are points that do not all lie in a single line.
Points M, N, O, and U lie on plane L, so you can choose any 3 of the 4 points to name the plane with, but make sure all 3 points are non-collinear.
To name plane L with points, you cannot use points MNO together since they are collinear, but you can name it using point U plus any two of the points M, N, and O.
plane L can be named
plane MOU
plane MNU
plane NOU
Do not name it plane MNO
the parallel line is 2x+5y+15=0.
Step-by-step explanation:
ok I hope it will work
soo,
Solution
given,
given parallel line 2x+5y=15
which goes through the point (-10,1)
now,
let 2x+5y=15 be equation no.1
then the line which is parallel to the equation 1st
2 x+5y+k = 0 let it be equation no.2
now the equation no.2 passes through the point (-10,1)
or, 2x+5y+k =0
or, 2*-10+5*1+k= 0
or, -20+5+k= 0
or, -15+k= 0
or, k= 15
putting the value of k in equation no.2 we get,
or, 2x+5y+k=0
or, 2x+5y+15=0
which is a required line.
