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masha68 [24]
3 years ago
10

Pls help being timed

Mathematics
2 answers:
Vera_Pavlovna [14]3 years ago
6 0

4x = 300*99

x= 300*99/4 = 7425.

So a is correct asnwer

Anastaziya [24]3 years ago
3 0

the answer is 7425

and the way we get this is by cross multiplying

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-18x-17=-53
nydimaria [60]

-18x-17=-53 /add 17 to both sides

-18x-17+17=-53+17

-18x=-36

x=(-36)/(-18)

x=2

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3 years ago
Solve for a. Assume that a, b and c are not zero. abc=c
sweet-ann [11.9K]
First you would divide everything by bc on both sides to get a by it self. Then you answer will be a=c/bc
4 0
3 years ago
Find the value of x. Then find the measure of each labeled angle
Artyom0805 [142]

Step-by-step explanation:

Question 10 :

3x + 6 = 4x – 12 ( reason: corresponding angles due to parallel lines)

simplify and get x, thus x = 18

to find 3x + 6 or 4x - 12(which is both the same),

3(18) + 6 = 60° , 4(18) - 12 = 60°

Question 11:

2x + 24 + x = 180 ( reason: interior angles due to parallel lines)

simplify again to get x, you will get x = 52

then find the individual by subbing in the value of x into the equation.

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7 0
3 years ago
Can someone please help me with this question
ElenaW [278]
A,C,B
A’s unit rate is 11.0667
C’s unit rate is 12.009
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3 0
3 years ago
Read 2 more answers
In △ABC, point D∈AC
Maslowich
<h3>Answer:</h3>
  • ABDC = 6 in²
  • AABD = 8 in²
  • AABC = 14 in²
<h3>Explanation:</h3>

A diagram can be helpful.

When triangles have the same altitude, their areas are proportional to their base lengths.

The altitude from D to line BC is the same for triangles BDC and EDC. The base lengths of these triangles have the ratio ...

... BC : EC = (1+5) : 5 = 6 : 5

so ABDC will be 6/5 times AEDC.

... ABDC = (6/5)×(5 in²)

... ABDC = 6 in²

_____

The altitude from B to line AC is the same for triangles BDC and BDA, so their areas are proportional to their base lengths. That is ...

... AABD : ABDC = AD : DC = 4 : 3

so AABD will be 4/3 times ABDC.

... AABD = (4/3)×(6 in²)

... AABD = 8 in²

_____

Of course, AABC is the sum of the areas of the triangles that make it up:

... AABC = AABD + ABDC = 8 in² + 6 in²

... AABC = 14 in²

6 0
3 years ago
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