Question

Pls help ffffffffffffffffffffffffffffffffffffffffffffff

Answer 1

Answer:

• Linear functions can be represented by a straight line, with an intercept and a constant slope. They are formed by a dependent varible (y) and an independent varible (x) whose power equals one, which means that y is related to x in a linear way (they have both power equal to one).
• The general equation of a linear function can be written as follows:        y= a + b x, with a equal to a constant known as the intercept, and b equal to the slope.
• We can rewrite the equations you have attached as follow, by rearranging terms in order to clear y as a function of x (in order):

1. $y=-19+\frac{1}{2}x$,  is a linear function: y is linked to x in a linear way, the curve has the form y= a + b x, where a=-19 and b=1/2.
2. $y=\frac{1}{3} x^{2}$, it is NOT a linear function, because y is linked to x in a way that is not linear (the power of x is different from zero, in this case the power of x equals 2 ), and the graph of this expression would not be linear.
3. $y=\frac{1}{39}x +\frac{5}{13}$ is a linear function: y is linked to x in a linear way (the power of x equals one), the curve in this case has the form y= a + b x, where a=1/39 and b=5/13.
4. $y=x+\frac{25}{5}$ is a linear function: y is linked to x in a linear way (the power of x equals one), and the curve has the form y= a + b x, where a=25/5 and b=1.
5. $y=\sqrt[3]{x}$ is NOT a linear function, because y is linked to x in a nonlinear way, specifically, y is linked to the squared root of x, which means that is linked to $x^{\frac{1}{3} }$, then x has not power equal to one in this case.