Answer:
B
Step-by-step explanation:
SSS stand for Side Side Side, so the truangle must identify all it's sides. To identify sides it uses lines through the side like in B where 1 side has 1 line, 1 side has 2 lines, and the other side has 3 lines. That is the side identifiers, and because each side in B matches with 1 side in A, means that A and B are congruent because they have the same sides, so SSS.
This is confusing to explain, if you have any questions post them in the comments.
Answer:
1.8 Kg
Step-by-step explanation:
a week- 3kg rice
every day-0.6 kg rice
therefore, multiply 3 kg by 0.6kg
3kg x 0.6kg =1.8 kg
he will have 1.8 kg rice after 4 days
have a great day !
Answer:
![f(3)=2\frac{2}{3}](https://tex.z-dn.net/?f=f%283%29%3D2%5Cfrac%7B2%7D%7B3%7D)
Step-by-step explanation:
![f(x)=8x\\f(3)=8(\frac{1}{3})\\f(3)=\frac{8}{3} \\f(3)=2\frac{2}{3}](https://tex.z-dn.net/?f=f%28x%29%3D8x%5C%5Cf%283%29%3D8%28%5Cfrac%7B1%7D%7B3%7D%29%5C%5Cf%283%29%3D%5Cfrac%7B8%7D%7B3%7D%20%5C%5Cf%283%29%3D2%5Cfrac%7B2%7D%7B3%7D)
Hope this helps!
The answer is 36 all you do is divide the answer choices by 3 to get your answer
Answer:
0.0707 radians
Step-by-step explanation:
Given that:
The dimension of the rectangular box is:
length (l) = 20 inches
width (w) = 20 inches
height (h) = 2 inches
The length of the diagonal of the rectangular box is :
![D_1 = \sqrt{ l^2+w^2+h^2}](https://tex.z-dn.net/?f=D_1%20%3D%20%20%5Csqrt%7B%20l%5E2%2Bw%5E2%2Bh%5E2%7D)
![D_1 = \sqrt {(20)^2+(20)^2+(2)^2}](https://tex.z-dn.net/?f=D_1%20%3D%20%5Csqrt%20%7B%2820%29%5E2%2B%2820%29%5E2%2B%282%29%5E2%7D)
![D_1 = \sqrt {400+400+4}](https://tex.z-dn.net/?f=D_1%20%3D%20%5Csqrt%20%7B400%2B400%2B4%7D)
![D_1 = \sqrt {804}](https://tex.z-dn.net/?f=D_1%20%3D%20%5Csqrt%20%7B804%7D)
![D_1 = 28.35](https://tex.z-dn.net/?f=D_1%20%3D%2028.35)
The length of the diagonal of the base of the rectangular box is:
![D_2 = \sqrt{l^2+w^2}](https://tex.z-dn.net/?f=D_2%20%3D%20%5Csqrt%7Bl%5E2%2Bw%5E2%7D)
![D_2 = \sqrt{(20)^2+(20)^2}](https://tex.z-dn.net/?f=D_2%20%3D%20%5Csqrt%7B%2820%29%5E2%2B%2820%29%5E2%7D)
![D_2 = \sqrt{400+400}](https://tex.z-dn.net/?f=D_2%20%3D%20%5Csqrt%7B400%2B400%7D)
![D_2 = \sqrt{800}](https://tex.z-dn.net/?f=D_2%20%3D%20%5Csqrt%7B800%7D)
![D_2 = 28.28](https://tex.z-dn.net/?f=D_2%20%3D%2028.28)
If we take a critical look at a rectangular box; we will realize that the diagonal of the base is the adjacent side & diagonal of the box is the hypotenuse of a triangle formed by the rectangular box.
Therefore, the angle between them is :
![Cos \theta = \frac{Diagonal \ of \ the \ base \ }{Diagonal \ of \ the \ box }](https://tex.z-dn.net/?f=Cos%20%5Ctheta%20%3D%20%5Cfrac%7BDiagonal%20%5C%20of%20%5C%20the%20%5C%20base%20%5C%20%20%7D%7BDiagonal%20%5C%20of%20%5C%20the%20%5C%20box%20%7D)
![Cos\ \theta = \frac{D_2}{D_1 }](https://tex.z-dn.net/?f=Cos%5C%20%20%5Ctheta%20%3D%20%5Cfrac%7BD_2%7D%7BD_1%20%7D)
![Cos\ \theta = \frac{28.28}{28.35 }](https://tex.z-dn.net/?f=Cos%5C%20%20%5Ctheta%20%3D%20%5Cfrac%7B28.28%7D%7B28.35%20%7D)
![Cos\ \theta = 0.9975](https://tex.z-dn.net/?f=Cos%5C%20%20%5Ctheta%20%3D%200.9975)
![\theta = Cos^{-1} \ 0.9975](https://tex.z-dn.net/?f=%5Ctheta%20%3D%20Cos%5E%7B-1%7D%20%5C%20%200.9975)
to radians
![\theta = 0.0707 \ radians](https://tex.z-dn.net/?f=%5Ctheta%20%3D%200.0707%20%5C%20radians)