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masya89 [10]
4 years ago
8

Solve for x: 125^(3x+7)=25^(5x−11)

Mathematics
1 answer:
vodomira [7]4 years ago
6 0

Answer:

x = 43

Step-by-step explanation:

125^(3x+7)=25^(5x−11)

Rewriting the bases as powers of 5

125 = 5^3  and 25 = 5^2

5^3 ^ (3x+7) = 5^2^(5x-11)

We know a^b^c = a^ (b*c)

5^(3 * (3x+7)) = 5^(2*(5x-11))

Distribute

5^(9x+21) = 5^(10x-22)

The bases are the same so the exponents are the same

9x+21 = 10x-22

Subtract 9x from each side

9x+21 -9x = 10x-9x-22

21 = x-22

Add 22 to each side

21+22 = x-22+22

43 = x

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4 0
4 years ago
A bag contains 10 red 6 green 12 orange and 8 purple candy's without looking Ann pulls one piece of candy out of the bag what is
Alex73 [517]

Answer:

\frac{1}{6}

Step-by-step explanation:

GIVEN: A bag contains 10 red 6 green 12 orange and 8 purple candies, without looking Ann pulls one piece of candy out of the bag.

TO FIND: what is the probability that she pulls out a purple piece of candy.

SOLUTION:

Total number of candies in the bag =36

Total number of purple candies in the bag =6

Now,

Probability that Ann pulls out a purple piece of candy

                                                                                        =\frac{\text{number of purple candies}}{\text{total candies in bag}}

putting values,

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                                                                                        =\frac{1}{6}

Hence, the probability that she pulls out a purple piece of candy is   \frac{1}{6}

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Step-by-step explanation:

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Answer:

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320 is the "old" value and 349 is the "new" value.

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