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lara31 [8.8K]
4 years ago
7

Please help with this question!

Mathematics
1 answer:
Rashid [163]4 years ago
3 0

Answer:

look at this image↗️↗️↗️↗️↗️↗️↗️↗️↗️↗️↗️

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The dimensions of a box are x, 2x, and 3x. Each dimension is decreased by 2. Calculate the volume of the box.
OLga [1]

Answer:

Correct choice is C) 6x^3-22x^2+24x-8.

Step-by-step explanation:

Given that the dimensions of a box are x, 2x, and 3x.

Now each dimension is decreased by 2.

Then new dimensions of a box are (x-2), (2x-2), and (3x-2).

Now let's calculate the volume of the box which is given by

Volume = (Length) x (Width) x (Height)

=(x-2)(2x-2)(3x-2)

=(2x^2-6x+4)(3x-2)

=(2x^2-6x+4)(3x-2)

=6x^3-22x^2+24x-8

Hence correct choice is C) 6x^3-22x^2+24x-8.

3 0
4 years ago
Calculate the volume of the composite shape<br> please please help giving brainliest!!
Ilya [14]

{\qquad\qquad\huge\underline{{\sf Answer}}}

There are two hemispheres in there with radius 3 cm, so we can consider it as a whole one. and the other shape in between is Cylinder with radius 3 cm and height 4 cm.

Volume of whole ahape = volume of Cylinder + volume of sphere ~

<u>Volume</u> <u>of</u> <u>sphere</u> :

\qquad \sf  \dashrightarrow \:  \cfrac{4}{3} \pi {r}^{3}

\qquad \sf  \dashrightarrow \:  \cfrac{4}{3}  \sdot3.14 \sdot {(3)}^{3}

\qquad \sf  \dashrightarrow \: (4 )\sdot(3.14) \sdot(9)

\qquad \sf  \dashrightarrow \: 113.04 \:  \: cm {}^{3}

<u>Volume</u> <u>of</u> <u>Cylinder</u> :

\qquad \sf  \dashrightarrow \: \pi {r}^{2} h

\qquad \sf  \dashrightarrow \: 3.14 \cdot(3) {}^{2}  \sdot4

\qquad \sf  \dashrightarrow \: 3.14 \sdot(9) \sdot(4)

\qquad \sf  \dashrightarrow \: 113.04 \:  \: cm {}^{3}

<u>Volume</u> <u>of</u> <u>whole</u> <u>shape</u> :

\qquad \sf  \dashrightarrow \: 113.04 + 113.04 = 226.08 \:  \: cm {}^{3}

\qquad \sf  \dashrightarrow \:  226.08 \:  \: cm {}^{3}

8 0
2 years ago
Factoring Trinomials (<br> Factor each completely.<br> 1) 3p² – 2p - 5
Maurinko [17]
3p^2 - 2p - 5
3p^2 -5p+3p-5 (5 times 3 equals 15)
p(3p-5) +1(3p-5)
Answer:
(3p - 5)(p + 1)
8 0
3 years ago
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Given the equation -4Square root x-3=12, solve for x and identify if it is an extranous solution
Nitella [24]
-4sqrt(x)-3 = 12 -> sqrt(x) - 3 = -3  -> sqrt(x) = 0
so x = 0, only solution, no extraneous solution
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4 years ago
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PLEASE HELP !!!!!
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Every hour it snowed O.5 inch ;)
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