Question

The dimensions of a box are x, 2x, and 3x. Each dimension is decreased by 2. Calculate the volume of the box.

Answer 1

Answer:

Correct choice is C) $6x^3-22x^2+24x-8$.

Step-by-step explanation:

Given that the dimensions of a box are x, 2x, and 3x.

Now each dimension is decreased by 2.

Then new dimensions of a box are (x-2), (2x-2), and (3x-2).

Now let's calculate the volume of the box which is given by

Volume = (Length) x (Width) x (Height)

$=(x-2)(2x-2)(3x-2)$

$=(2x^2-6x+4)(3x-2)$

$=(2x^2-6x+4)(3x-2)$

$=6x^3-22x^2+24x-8$

Hence correct choice is C) $6x^3-22x^2+24x-8$.