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rusak2 [61]
3 years ago
5

Does a proportional relationship have a constant rate of change?

Mathematics
1 answer:
Zarrin [17]3 years ago
5 0
Yes it does and ipthe equation also is y=kx or k=yx
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12 Two plumbers received a job. At first, one of the plumbers worked alone for 1 hour, and then they worked together for the nex
Degger [83]
The answer should be 12
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3 years ago
If g(x) is a linear function such that g(-3) = 2 and g(1) = -4, find g(7).
eimsori [14]
<h3>Answer:   -13</h3>

=======================================

Explanation:

g(-3) = 2 means x = -3 and y = 2 pair up together to form the point (-3,2)

g(1) = -4 means we have the point (1,-4)

Find the slope of the line through the two points (-3,2) and (1,-4)

m = (y2-y1)/(x2-x1)

m = (-4-2)/(1-(-3))

m = (-4-2)/(1+3)

m = -6/4

m = -3/2

m = -1.5

The general slope intercept form y = mx+b turns into y = -1.5x+b after replacing m with -1.5

Plug in (x,y) = (-3,2) which is one of the points mentioned earlier and we end up with this new equation:  2 = -1.5*(-3) + b

Let's solve for b

2 = -1.5*(-3)+b

2 = 4.5 + b

2-4.5 = 4.5+b-4.5 .... subtract 4.5 from both sides

-2.5 = b

b = -2.5

Therefore, y = mx+b becomes y = -1.5x-2.5 meaning the g(x) function is g(x) = -1.5x-2.5

The last step is to plug in x = 7 and compute

g(x) = -1.5*x - 2.5

g(7) = -1.5*7 - 2.5

g(7) = -10.5 - 2.5

g(7) = -13

6 0
3 years ago
Read 2 more answers
Write the slope intercept form through: (5,1) and(2, -2)
victus00 [196]

We see that the slope of this line is \frac{-2-1}{2-5}=1, so we plug this and the point (5,1) into the point-slope form y-y_1=m(x-x_1) (note that there's nothing special about the point I picked; you can choose any point on the line):

y-1=x-5. This rearranges to the slope-intercept form \boxed{y=x-4}.

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Akimi4 [234]

Answer:

-8x -16

-8( x + 2 )

......

4 0
3 years ago
Solve the system of equations -x - 2y = 11 and -3x - 2y = -7
rjkz [21]
Answer: (9,-10) or x=9...y=-10
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3 years ago
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