Answer:
a) Matrix B = ![\left[\begin{array}{c}5\\7\\9\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D5%5C%5C7%5C%5C9%5Cend%7Barray%7D%5Cright%5D)
b) Matrix AB = ![\left[\begin{array}{c}2525\\3620\\2845\\3705\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D2525%5C%5C3620%5C%5C2845%5C%5C3705%5Cend%7Barray%7D%5Cright%5D)
c) $12,695
Step-by-step explanation:
Matrix A = ![\left[\begin{array}{ccc}225&110&70\\95&160&225\\280&65&110\\0&240&225\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D225%26110%2670%5C%5C95%26160%26225%5C%5C280%2665%26110%5C%5C0%26240%26225%5Cend%7Barray%7D%5Cright%5D)
a) Matrix B =
Gross Receipt = AB
. =
c) Total revenue is the sum of receipts from 4 cinemas given in part b
Hence,
Total revenue = $2525 + $3620 + $2845 + $3705 = $12,695
Answer:
12:00 am midnight
Step-by-step explanation:
Given;
I can read a 336-page book in 6 hours.
My rate r1 = 336/6 pages per hour = 56 pages per hour
Jayne can read a 144-page book in 3 hours.
Jayne rate r2 = 144/3 = 48 pages per hour
If I start reading a 5000-page book at noon and Jayne starts reading the same book at 10 AM
Taking 10 am as the reference time.
Let x represent the time from 10 am at which they would both be on the same page.
For me;
Since i started by noon; 2 hours after 10 am
Time t1 = x-2
For Jayne;
She started by 10 am
Time t2 = x
For them to be on the same page they must have read the same number of pages;
Number of pages read = rate × time
r1(t1) = r2(t2)
Substituting the values;
56(x-2) = 48(x)
56x - 112 = 48x
x(56-48) = 112
x = 112/(56-48)
x = 14 hours
Since 10 am is the reference, the time would be;
=10 am + x = 10 am + 14 hours
= 24:00
= 12:00 am midnight
3x6=18
6x2=12
The answer is 30 sqft
