<u>Question: Solve the inequality 10(z + 3) ≥ 10z + 19.</u>
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<em>Answer:</em> <em>The answer to your question is "All Real Numbers". Please see the attachment below for all the steps provided. Since 0≥-11, this means that, "All Real Numbers; [Numbers greater or equal to 1] are going to be greater than -11. Thus, meaning that the answer is </em><em>All Real Numbers.</em>
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I can’t see make clearer plz
Answer:
The proof is explained step-wise below :
Step-by-step explanation :
For better understanding of the solution see the attached figure :
Given : ABCD is a Parallelogram ⇒ AB ║ DC and AD ║ BC
Now, F lies on the extension of DC. So, AB ║ DF
To Prove : ΔABE is similar to ΔFCE
Proof :
Now, in ΔABE and ΔFCE
∠ABE = ∠FCE ( alternate angles are equal )
∠AEB = ∠FEC ( Vertically opposite angles )
So, by using AA postulate of similarity of triangles
ΔABE is similar to ΔFCE
Hence Proved.
You could use the solution of 9/4 times 2