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barxatty [35]
3 years ago
7

Is this true 2.01 < 2.2

Mathematics
1 answer:
AlexFokin [52]3 years ago
7 0

Answer: True

Let's make 2.2 into a three digit number to calculate and focus better.

⇒ 2.01 < 2.20

2.20 is 0.19 more than the number/decimal 2.01.

So, the answer is True. 2.2 is greater than 2.01.

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Find the modulus of the complex number 6-2i
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Answer:

The modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

Step-by-step explanation:

Given the number

6-2i

We know that

z = x + iy

where x and y are real and \sqrt{-1}=i

The modulus or absolute value of z is:

|z|\:=\sqrt{x^2+y^2}

Therefore, the modulus of 6-2i  will be:

z=6-2i

z=6+(-2)i

|z|\:=\sqrt{x^2+y^2}

|z|\:=\sqrt{6^2+\left(-2\right)^2}

    =\sqrt{6^2+2^2}

    =\sqrt{36+4}

    =\sqrt{40}

    =\sqrt{2^2}\sqrt{2\cdot \:5}

    =2\sqrt{2\cdot \:5}

   =2\sqrt{10}

Therefore, the modulus of the complex number 6-2i is:

|z|\:=2\sqrt{10}

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