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Elodia [21]
3 years ago
13

Without graphing determine whether the system of linear equations has one solution infinitely many solutions or no solution expl

ain your reasoning.
y=4x+8
y=5x+1
Mathematics
2 answers:
N76 [4]3 years ago
8 0

Answer:

Infinitely many solutions.

Step-by-step explanation:

First, make both equations equal to each other.

4x + 8 = 5x + 1

Subtract 4x from both sides.

8 = x + 1

Subtract 1 from both sides.

7 = x


When x > 0, there are infinitely many solutions.

When x = 0, there is only one solution.

When x < 0, there are no solutions.


In this case, x = 7, and 7 > 0. Therefore there are infinitely many solutions.

hodyreva [135]3 years ago
5 0
The answer for this is 9x=9
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<h2><em><u>Option</u></em><em><u> </u></em><em><u>B</u></em><em><u>:</u></em></h2><h3><em><u>112</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em></h3>

Step-by-step explanation:

<em><u>Given</u></em><em><u>,</u></em>

No. of families = 75

Out of 75 no. of families had cars = 42

Out of 1, no. of families can have cars

=  \frac{42}{75}

<em><u>Therefore</u></em><em><u>, </u></em>

Out of 200 families, no. of families had cars

= 200 \times  \frac{42}{75}

=200 \times   \frac{14}{25}

= 8 × 14

= 112

<em><u>Hence</u></em><em><u>, </u></em>

<em><u>option</u></em><em><u> </u></em><em><u>B</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>correct</u></em><em><u> </u></em><em><u>as</u></em><em><u> </u></em><em><u>112</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em><em><u>have</u></em><em><u> </u></em><em><u>cars</u></em><em><u> </u></em><em><u>out</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>200</u></em><em><u> </u></em><em><u>families</u></em><em><u> </u></em><em><u>(</u></em><em><u>Ans</u></em><em><u>)</u></em>

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3 years ago
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