All categories

2 years ago

Write x(x+1)^2(x-5)/x(x+2)(x-5)^3 in simplest terms. Show your work

Mathematics

2 answers:

Simora [160]2 years ago

4 0

Answer: (x+1)^2(x-5)^4(x+2)

Step-by-step explanation: 1. Cancel x (x+1)^2(x-5)(x+2)(x-5)^3

Use The product Rule: x^a x^b= x ^a+^b and your answer should be (x+1)^2(x-5)^4(x+2)

Elena L [17]2 years ago

4 0

Simplify Expression
Answer (x+1)^2/(x+2)(x-5)^2

Cancel common factor of x
Rewrite expression
Factor
Cancel common factors …. It basically repeats !

You might be interested in

Find the value of A if A=1\2bh, b=8 and h= 9

katrin [286]

A=36 1/2*8*9 this is how you would figure out A

8 0

3 years ago

A bag of potatoes weighs 9.42 pounds on a weighing scale. Which of the significant digits in the scale reading is the least reli

rjkz [21]

The 2 because we don't know if it is exactly two or if was was rounded up/ down to 2.

4 0

3 years ago

Read 2 more answers

A zoo in oklahoma charged $22 for adults and $15 for children. During a summer day, 732 zoo tickets were sold, and the total rec

Vlad [161]

Answer: Cost of tickets for adults = $22

Cost of tickets for children = $15

Total number of tickets sold = 732

Total receipts = $12,912

Let x be number of adult ticket's sold and y be the number of child ticket's sold.

Therefore, we have:

$x+y=732$ --------------- equation 1

$x=732-y$

Also, we have:

$22 x+15y=12,912$

Now, let's substitute the value of x:

$22 (732-y)+15y=12912$

$16104-22y+15y=12912$

$16104-7y=12912$

$7y=16104-12912$

$7y=3192$

$y=\frac{3192}{7} =456$

Now, let's substitute the value of y=456 in equation 1, we have:

$x+456=732$

$x=732-456$

$x=276$

Therefore, the number of child ticket's sold is 456 and number of adult ticket's sold is 276

6 0

3 years ago

Easton is working two summer jobs, making $18 per hour tutoring and $9 per hour clearing tables. Last week Easton worked 4 times

Mama L [17]

Answer:

the new Zealand international was the first time he had scored in a day and a half century for any of his

7 0

3 years ago

The tables below show four sets of data:

vovangra [49]

Answer:

Hence, the set that represent a negative linear association between x and y is:

Set A.

Step-by-step explanation:

We are given 4 sets of data as:

Set A

x 1 2 3 4 5 6 7 8 9

y 10 9 8 7 6 5 4 3 2

Set B

x 1 2 3 4 5 6 7 8 9

y 3 4 5 6 7 8 9 10 11

Set C

x 1 2 3 4 5 6 7 8 9

y 8 6 5 4 3.5 3 2.5 2 2

Set D

x 1 2 3 4 5 6 7 8 9

y 1 2.5 2.5 3 4 5 6 8 9

We are asked to determine the set which represent negative linear association between x and y?

Clearly in Set B and Set D the values of y keeps on increasing as the value of x increases; hence they both represent a positive linear association between x and y.
In set C the relationship is non-linear though it is negative.
Clearly in Set A we could see that the the y is related to x as:

y=11-x or y= -x+11.

Hence, clearly we could see that the relationship is linear and also negative as the value of y keeps on decreasing with increasing x.

Hence, the set that represent a negative linear association between x and y is:

Set A.

3 0

3 years ago

Read 2 more answers