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lana66690 [7]
3 years ago
11

Pleaseeeee helpppppp

Mathematics
1 answer:
Tju [1.3M]3 years ago
6 0
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Please answer..............
Schach [20]

Answer:

Step-by-step explanation:

angle v is 133

angle x is 102

angle y is 136

4 0
3 years ago
Read 2 more answers
HOW DO YOU FIND THE SINE, COSINE, AND TANGENT VALUES GIVEN A POINT ON A CIRCLE? BE ABLE TO PROVIDE AN EXAMPLE.
FromTheMoon [43]
Answer: If the point of the circle P has coordinates: P=(x,y)
sine (Angle) = y/r
cosine (Angle) = x/r
tangent (Angle) = y/xw
where r=sqrt(x^2+y^2) is the radius of the circle

Example:
P=(3,4)=(x,y); x=3 and y=4
Radius of the circle: r
r=sqrt(x^2+y^2)
r=sqrt(3^2+4^2)
r=sqrt(9+16)
r=sqrt(25)
r=5

sin(Angle)=y/r
sin(Angle)=4/5

cosine(Angle)=x/r
cosine(Angle)=3/5

tangent(Angle)=y/x
tangle(Angle)=4/3
4 0
4 years ago
Read 2 more answers
Let f(x)=-∛X what is the average rate of change of f(x) from 8 to 64
Harrizon [31]

if you multiply each x by -5 you will get each y

hope this helps and can i get a Brainliest because in don't have any

5 0
3 years ago
Simplify the expression.<br> a)1/64<br> b)2^-30<br> c)64<br> d)2^30
Korolek [52]

\left(\dfrac{(-1)^5}{(-2)^{-3}} \right)^2\\\\\\=\left(\dfrac{-1}{\dfrac{1}{(-2)^3}} \right)^2\\\\\\=\left(-1 \times -8\right)^2\\\\=8^2\\\\=64

6 0
3 years ago
Read 2 more answers
Volume and surface area are often compared by manufacturers in order to maximize how much of something can go inside of a packag
notka56 [123]
We have no dimensions to work with. I'll pick some and try and comply with the conditions of the problem. 

Suppose you have an object that is 14 by 22 by 27 cm. These three numbers have no common factor so they cannot be reduced any further, which is helpful for this problem.

Find the Volume
Volume

l = 27 cm
w = 14 cm
h = 22 cm

V = 27 *14 * 22
V = 8316 cm^3

Find the surface area
SA = 2*l*w + 2*l*h  + 2*w*h
SA = 2*27*14  +  2*27*22   +  2*14*22
SA = 756 + 1188 + 616
SA = 2558

Just looking at these numbers The surface area is about 1/3 of the volume. I don't think this is always true.


 \frac{SA}{V} =  \frac{2*L*W  + 2*L*H + 2*W*H}{L*W*H} 

Another way to do this is to consider a cube which might give you a more useful result. 

s = L = W = H all three dimensions are equal in a cube.
The volume of a cube is s*s*s = s^3
The surface area of a cube is 2*s*s + 2*s*s + 2s*s = 6s^2

\frac{SA_cube}{V_cube} =  \frac{6s*s}{s*s*s}
\frac{SA}{V} =  \frac{6}{s}

That means whatever the side length, the Surface Area to volume = 6/the side length which is kind of an interesting result.


4 0
3 years ago
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