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Andreyy89
3 years ago
5

A warehouse worker ships 25 boxes each day. Every box contains 3 shipping labels. Inventory has 500 shipping labels. How many da

ys will it take to use the inventory of shipping labels? round to the nearest whole.
Mathematics
1 answer:
Stolb23 [73]3 years ago
4 0

Answer: It will take 7 days to use the inventory of shipping labels.

Step-by-step explanation:

Given : Total boxes shipped by warehouse worker per day = 25

Every box contains 3 shipping labels.

Inventory has 500 shipping labels.

Then, the total number of boxes can be made =  (Total  shipping labels) ÷ (labels in each box)

500 ÷ 3  =166.67≈166

Number of days it will take to use the inventory of shipping labels=  (total number of boxes can be made)  ÷  (Total boxes shipped  per day)

= 166÷ 25=6.64≈7

Hence, it will take 7 days to use the inventory of shipping labels.

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A candy store has 6 boxes of chocolates. Each box has 500 pieces How many pieces are there altogether in the 6 boxes?​
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Answer is 3,000 hope it helps
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2 years ago
If f(x) = 3x^2 + 1 and g(x) = 1 – x, what is the value of (f – g)(2)?
ziro4ka [17]
F - g(2) = 3x^2 + 1 - ( 1 - x )
= 3x^2 + 1 - 1 + x
= 3x^2 + x
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4 0
3 years ago
Suppose the horses in a large stable have a mean weight of 1467lbs, and a standard deviation of 93lbs. What is the probability t
krok68 [10]

Answer:

0.5034 = 50.34% probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this problem, we have that:

\mu = 1467, \sigma = 93, n = 49, s = \frac{93}{\sqrt{49}} = 13.2857

What is the probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable?

This is the pvalue of Z when X = 1467 + 9 = 1476 subtracted by the pvalue of Z when X = 1467 - 9 = 1458.

X = 1476

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{1476 - 1467}{13.2857}

Z = 0.68

Z = 0.68 has a pvalue of 0.7517

X = 1458

Z = \frac{X - \mu}{s}

Z = \frac{1458 - 1467}{13.2857}

Z = -0.68

Z = -0.68 has a pvalue of 0.2483

0.7517 - 0.2483 = 0.5034

0.5034 = 50.34% probability that the mean weight of the sample of horses would differ from the population mean by less than 9lbs if 49 horses are sampled at random from the stable

5 0
3 years ago
HELP!!<br> what is the value of w?<br> A.40<br> B.52.5<br> C.75<br> D.100
Inga [223]
The angles w and 80 are inscribed angles in the top left and bottom right corners respectively. They are opposite angles in this inscribed quadrilateral. Because they are opposite angles in the inscribed quadrilateral, they add to 180 degrees.

w+80 = 180
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w = 100

Answer: Choice D
6 0
3 years ago
Read 2 more answers
a survey of 504 citizens found that 378 of them favor a new bill introduced by the city. We want to find a 95% confidence interv
Viefleur [7K]

The lower limit of the interval is 0.712 if the survey of 504 citizens found that 378 of them favor a new bill introduced by the city.

<h3>What is a confidence interval?</h3>

It is defined as the sampling distribution following an approximately normal distribution for known standard deviation.

We have:

A survey of 504 citizens found that 378 of them favor a new bill introduced by the city.

Sample proportion = p = 378/504 = 0.75

q = 1 - p = 1 - 0.75 = 0.25

\rm SD = \sqrt{\dfrac{pq}{n}}

\rm SD = \sqrt{\dfrac{0.75\times0.25}{504}}

SD = 0.01928

For 95% confidence interval Z value = 1.96

Lower limit = 0.75 - 1.96(0.01928)

= 0.712

Thus, the lower limit of the interval is 0.712 if the survey of 504 citizens found that 378 of them favor a new bill introduced by the city.

Learn more about the confidence interval here:

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2 years ago
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