Answer:
Part A
= 9 flowers
Part B
= 5 flowers
Step-by-step explanation:
Emily has 59 flowers. She wants to put the flowers in 6 vases with the same number in each vase.
Part A: What is the greatest number of flowers she can put in each vase?
This is calculated as:
59 flowers ÷ 6 vases
= 9 5/6 flowers
Therefore, the greatest number of flowers she can put in each vase is 9 flowers
Part B: How many flowers will Emily have left over?
We have to calculate the number of flowers in the 6 vases above
= 9 flower × 6
= 54 flowers
Hence:
= 59 flowers - 54 flowers
= 5 flowers
Therefore, Emily would have 5 flowers left over.
Answer: 
<u>Step-by-step explanation:</u>
cos x tan x - cos x = 0
cos x (tan x - 1) = 0
cos x = 0 tan x - 1 = 0
tan x = 1
Answer:
5 units (you are right!)
Step-by-step explanation:
The triangles ABD and BCD are similar.
Therefore,
I hope this helped!
Step-by-step explanation:
<h2><u>Given :-</u></h2>
(√3-√2)/(√3+√2)
<h2><u>To find :-</u></h2>
Rationalised form = ?
<h2><u>Solution:-</u></h2>
Given that
(√3-√2)/(√3+√2)
The denominator = √3+√2
The Rationalising factor of √3+√2 is √3-√2
On Rationalising the denominator then
=> [(√3-√2)/(√3+√2)]×[(√3-√2)/(√3-√2)]
=> [(√3-√2)(√3-√2)]×[(√3+√2)(√3-√2)]
=> (√3-√2)²/[(√3+√2)(√3-√2)]
=> (√3-√2)²/[(√3)²-(√2)²]
Since (a+b)(a-b) = a²-b²
Where , a = √3 and b = √2
=> (√3-√2)²/(3-2)
=> (√3-√2)²/1
=> (√3-√2)²
=> (√3)²-2(√3)(√2)+(√2)²
Since , (a-b)² = a²-2ab+b²
Where , a = √3 and b = √2
=> 3-2√6+2
=> 5-2√6
Hence, the denominator is rationalised.
<h2>
<u>Answer</u><u>:</u></h2>
Rationalised form of (√3-√2)/(√3+√2) is 5 - 2√6.
<h2><u>U</u><u>sed </u><u>formulae:</u><u>-</u></h2>
- (a+b)(a-b) = a²-b²
- (a-b)² = a²-2ab+b²
- The Rationalising factor of √3+√2 is √3-√2
For a vector-valued function
the matrix of partial derivatives (a.k.a. the Jacobian) is the 
matrix in which the 
-th entry is the derivative of 
with respect to 
:
So we have
(a)
(b)
(c)
(d)
