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4 years ago

15

When the null hypothesis is true and n is greater than or equal to 5 per group, the test statistic for the Friedman test is appr

oximately distributed as a
(A)t-distribution

(B)F-distribution

(C)normal distribution

(D)chi-square distribution

1 answer:

MAXImum [283]4 years ago

7 0

Answer:

D

Step-by-step explanation:

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Write an equation for a line passing through (-4, 3) and (0, 6)

Elena L [17]

Answer:

y = 3/4x + 6

Step-by-step explanation:

6-3 3

------- = ------

0--4 4

y = mx + b

take coordinates for y and x out of (-4, 3) or (0,6)

6= 3/4 * 0 + b

6 = 0 + b

b = 6

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3 years ago

Evaluate cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

Andre45 [30]

Answer:

Option d) 5 to the power of negative 5 over 6 is correct.

$\dfrac{\sqrt[3]{\bf 5} \times \sqrt{\bf 5}}{\sqrt[3]{\bf 5^{\bf 5}}}= 5^{\frac{\bf -5}{\bf 6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

ie, $5^\frac{\bf -5}{\bf 6}$

Step-by-step explanation:

Given that cube root of 5 multiplied by square root of 5 over cube root of 5 to the power of 5.

It can be written as below

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}} \times 5^{\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{1}{3}+\frac{1}{2}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= \dfrac{5^{\frac{2+3}{6}}}{5^{\frac{5}{3}}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5}{6}} \times 5^{\frac{-5}{3}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{\sqrt[3]{5^5}}= 5^{\frac{5-10}{6}}$

$\dfrac{\sqrt[3]{5} \times \sqrt{5}}{5^5}= 5^{\frac{-5}{6}}$

Above equation can be written as 5 to the power of negative 5 over 6.

7 0

4 years ago

Graph the line with slope of 5/3 and goes through the point (2,1).

sladkih [1.3K]

Answer:

so graph your first point. (x=2, y=1)

Step-by-step explanation:

Your 5/3 is your rise over run. So go up 5 from 2 you should be at 7 and over 3 from your 1 so your next point would be (x=7, y=4) now get a ruler and connect your two points. make sure to use a ruler to make your line straight.

3 0

4 years ago

If you can buy 1⁄3 of a pound of turkey for 4 dollars, how much can you purchase for 10 dollars? Write your answer as a fraction

gulaghasi [49]

The answer is 5/6 of a pound.

3 0

3 years ago

Read 2 more answers

A town’s January high temperatures average 36 degrees (F) with a standard deviation of 10 degrees while in July the mean high

n200080 [17]

Answer:

55 degrees is more unusual in July as it is away from mean temperature as compared to January.

Step-by-step explanation:

We are given the following information in the question:

January:

Mean, μ = 36 degrees

Standard Deviation, σ = 10 degrees

July:

Mean, μ = 74 degrees

Standard Deviation, σ = 8 degrees

We calculate z scores corresponding to x = 55.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

January:

$z_{score} = \displaystyle\frac{55-36}{10} = 1.9$

July:

$z_{score} = \displaystyle\frac{55-74}{8} = -2.375$

Thus, 55 degrees is more unusual in July as it is away from mean temperature as compared to January.

3 0

4 years ago