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3 years ago

How many times can a nine go into a 20

1 answer:

4 0

A nine can go into a 20 two whole times. After that, there's still
some room left in the 20, but it's only enough room for a 2.

You might be interested in

Solve 3[-x + (2 x + 1)] = x - 1.

Marrrta [24]

Answer:

x= -2

Step-by-step explanation:

-3x+6x+3=x-1

3x-x= -1-3

2x= -4

x= -2

6 0

3 years ago

Read 2 more answers

Simplify 2 (n+1) + n² + 4 (n-3)

Gala2k [10]

2 (n+1) + n² + 4 (n-3)
= 2n + 2 + n² + 4n - 12 ...expand by using distributive property
= n² + 6n - 10 ...combine like terms

hope it helps

4 0

2 years ago

Read 2 more answers

Using the order of operations rule, solve the following: 12 ÷ 2 + 4 – 2 × 3 = ? A. 36 B. 0 C. 4 D. 24 Mark for review

AlexFokin [52]

<h2>Answer:</h2>

<u>The answer is </u><u>(C) 4</u>

<h2>Step-by-step explanation:</h2>

According to the rule of BODMAS

We will first do division then Multiplication then addition and in the last we do subtraction

12 ÷ 2 + 4 – 2 × 3 will be done as

= (12 ÷ 2) + 4( – 2 × 3)

= 6+4-6

= 4

5 0

3 years ago

Read 2 more answers

1. The probability of telesales representative making a sale on a customer call is 0.15.

Mumz [18]

Answer:

$n = 33$

$n = 19$

Step-by-step explanation:

From the question we are told that

The probability of telesales representative making a sale on a customer call is $p = 0.15$

The mean is $\mu = 5$

Generally the distribution of sales call made by a telesales representative follows a binomial distribution

i.e

$X \~ \ \ \ B(n , p)$

and the probability distribution function for binomial distribution is

$P(X = x) = ^{n}C_x * p^x * (1- p)^{n-x}$

Here C stands for combination hence we are going to be making use of the combination function in our calculators

Generally the mean is mathematically represented as

$\mu = n* p$

=> $5= n * 0.15$

=> $n = 33$

Generally the least number of calls that need to be made by a representative for the probability of at least 1 sale to exceed 0.95 is mathematically represented as

$P( X \ge 1) = 1 - P( X < 1 ) > 0.95$

=> $P( X \ge 1) = 1 - P( X =0 ) > 0.95$

=> $P( X \ge 1) = 1 - [ ^{n}C_0 * (0.15 )^0 * (1- 0.15)^{n-0}] > 0.95$

=> $1 - [1 * 1* (0.85)^{n}] > 0.95$

=> $[(0.85)^{n}] > 0.05$

taking natural log of both sides

$n = \frac{ln(0.05)}{ln(0.85)}$

=> $n = 19$

3 0

2 years ago

Algebra problem help

True [87]

To solve this problem you must apply the proccedure below:

1. You have that one canned juice drink is 20% orange juice and another is 5% orange juice.

2. You must make a system of equation, as below:

x+y=15 (i)
0.20x+0.05y=0.15x15 (ii)

3. Now, you must find the value of x (the liters of the first canned needed) and y (the liters of the other canned needed):

x+y=15 (i)
x=15-y

0.20x+0.05y=0.15x15 (ii)
0.20(15-y)+0.05y=2.25
y=5 liters

x+y=15 (i)
x=15-5
x=10 liters

4. Therefore, the asnwer is:

10 liters of the canned juice drink that is 20% orange juice and 5 liters of the other canned juice drink that is 5% orange juice.

4 0

2 years ago