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xeze [42]
3 years ago
15

What is an exact solution for

" alt="m \sqrt{14} " align="absmiddle" class="latex-formula">
​

Mathematics
1 answer:
AlexFokin [52]3 years ago
8 0

Answer: Choice B)  \sqrt{14}

We have some value m and we're squaring it to get m^2

To undo this and isolate m, we apply the square root to both sides

m^2 = 14\\\\\sqrt{m^2} = \sqrt{14}\\\\|m| = \sqrt{14}\\\\m = \sqrt{14} \text{ or } m = -\sqrt{14}

There are two solutions here. This is similar to how there are two solutions in something like x^2 = 25 (those two solutions being x = 5 and x = -5). Squaring any negative number leads to a positive result because

negative times negative = positive.

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On December 13, 2007, one British pound was worth 2.04 U.S. dollars.
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Answer:

a) 5 pounds

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2 years ago
Can somebody plz answer these questions correctly thanks!!
nadya68 [22]

Answer:

The decimal form of 3/5 is .6 or .60 and the percent form is 60%.

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4 0
3 years ago
Helppppp pleaseeeeeeewwwwwwwww
klemol [59]

Answer:

It should be 1,628 m^{2}.

Step-by-step explanation:

We see two shapes in the figure and those shapes are a rectangle and a circle. Let's find the area of the circle first. 25m won't help us find the area of the circle so let's pretend that 25m isn't there for now. 40m seems to be the diameter of the circle and to find the area of the circle we need to multiply the radius squared by Pi or 3.14. Half of 40 is 20 so we can multiply 20 squared by Pi to give us 1,256.63706. Do not round this number yet. As you can see this circle isn't a full circle. It's a semicircle. We can divide 1,256.63706 by 2 to find the area of a semicircle. You should get 628.31853 and round that to the nearest tenth and we get 628.32. Now let's keep that number in mind and find the area of the rectangle. Using a calculator we can easily multiply 40 and 25 to find the area of the rectangle, which is 1,000. Add 1,000 and 628.32 and our final results should be 1,628.32. I don't see this number in your options but option B is closely related to this answer. I hope this helps and if this answer is wrong then please give me some feedback on what I did wrong! Thank you!

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