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xeze [42]
3 years ago
15

What is an exact solution for

" alt="m \sqrt{14} " align="absmiddle" class="latex-formula">
​

Mathematics
1 answer:
AlexFokin [52]3 years ago
8 0

Answer: Choice B)  \sqrt{14}

We have some value m and we're squaring it to get m^2

To undo this and isolate m, we apply the square root to both sides

m^2 = 14\\\\\sqrt{m^2} = \sqrt{14}\\\\|m| = \sqrt{14}\\\\m = \sqrt{14} \text{ or } m = -\sqrt{14}

There are two solutions here. This is similar to how there are two solutions in something like x^2 = 25 (those two solutions being x = 5 and x = -5). Squaring any negative number leads to a positive result because

negative times negative = positive.

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Antoine works in a restaurant and he is paid his regular hourly rate of 40 hours a week and time and a half for all hours over 4
Inessa05 [86]
560+ 147= 707

14(40)= 560
14+ 14(1/2)=21
21(7)= 147
6 0
2 years ago
Persons taking a 30-hour review course to prepare for a standardized exam average a score of 620 on that exam. Persons taking a
Alina [70]

Given:

30-hour review course average a score of 620 on that exam.

70-hour review course average a score of 749.

To find:

The linear equation which fits this data, and use this equation to predict an average score for persons taking a 57-hour review course.

Solution:

Let x be the number of hours of review course and y be the average score on that exam.

30-hour review course average a score of 620 on that exam. So, the linear function passes through the point (30,620).

70-hour review course average a score of 749. So, the linear function passes through the point (70,749).

The linear function passes through the points (30,620) and (70,749). So, the linear equation is:

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

y-620=\dfrac{749-620}{70-30}(x-30)

y-620=\dfrac{129}{40}(x-30)

y-620=\dfrac{129}{40}(x)-\dfrac{129}{40}(30)

y-620=\dfrac{129}{40}(x)-\dfrac{387}{4}

Adding 620 on both sides, we get

y=\dfrac{129}{40}x-\dfrac{387}{4}+620

y=\dfrac{129}{40}x+\dfrac{2480-387}{4}

y=\dfrac{129}{40}x+\dfrac{2093}{4}

We need to find the y-value for x=57.

y=\dfrac{129}{40}(57)+\dfrac{2093}{4}

y=183.825+523.25

y=707.075

y\approx 707.1

Therefore, the required linear equation for the given situation is y=\dfrac{129}{40}x+\dfrac{2093}{4} and the average score for persons taking a 57-hour review course is 707.1.

4 0
2 years ago
Find ab if the coordinates of a are (3, 5 ( and b are (-3, -3)<br><br>a- 8<br>b- 6<br>c- 12<br>d- 10
strojnjashka [21]
If you use the distance formula you get 10.
6 0
3 years ago
The percent of decrease from 12 to 9.
MissTica
I’m pretty sure it’s 75%
7 0
3 years ago
Read 2 more answers
HELP ASAP ILL GIVE U BRAINLIEST AND A THANKS
Olenka [21]

Answer:

you have to write it down on a piece of paper and go from there

Step-by-step explanation:

5 0
3 years ago
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