Answer:
1. 1, 2, 5, 10
2. 1, 5, 25
3. 1, 2, 4, 8, 16, 32
4. 1, 3, 9, 27, 81
5. 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72
6. 1, 2, 4, 5, 10, 20, 25, 50, 100
7. 1, 5, 25, 125
8. 1, 2, 4, 11, 22, 44
Step-by-step explanation:
Hope this helps!
Answer:
since there is no image attached I can't see what weight they could be labeled but since the scale is even the weights must be the same number weight
Step-by-step explanation:
hope this helped!
The answers to each of the given problems are;
1) Sum of two smallest integers = 23
2) 3x + 6
3) 7.5 m/s²
<h3>How to find the sum of consecutive Integers?</h3>
1) We are told that sum of 4 consecutive integers is increased by 20 and equals 70. Thus, we have;
x + (x + 1) + (x + 2) + (x + 3) + 20 = 70
4x + 26 = 70
4x = 70 - 26
4x = 44
x = 44/4
x = 11
Thus, sum of two smallest integers = 11 + 11 + 1 = 23
2) Let the consecutive odd numbers be;
x, (x + 2) and (x + 4)
Sum of these consecutive odd numbers is;
x + x + 2 + x + 4 = 3x + 6
3) We are given the equation to find the acceleration as;
(v_final)² - (v_initial)² = 2ad
We are given;
v_final = 40 m/s
v_initial = 10 m/s
d = 100 m
Thus;
40² - 10² = 2a(100)
1500 = 200a
a = 1500/200
a = 7.5 m/s²
Read more about sum of integers at; brainly.com/question/17695139
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Its 7xy/1y I understand it its pretty easy
