Question

1.

Answer 1

The answers to each of the given problems are;

1) Sum of two smallest integers  = 23

2) 3x + 6

3) 7.5 m/s²

How to find the sum of consecutive Integers?

1) We are told that sum of 4 consecutive integers is increased by 20 and equals 70. Thus, we have;

x + (x + 1) + (x + 2) + (x + 3) + 20 = 70

4x + 26 = 70

4x = 70 - 26

4x = 44

x = 44/4

x = 11

Thus, sum of two smallest integers = 11 + 11 + 1 = 23

2) Let the consecutive odd numbers be;

x, (x + 2) and (x + 4)

Sum of these consecutive odd numbers is;

x + x + 2 + x + 4 = 3x + 6

3) We are given the equation to find the acceleration as;

(v_final)² - (v_initial)² = 2ad

We are given;

v_final = 40 m/s

v_initial = 10 m/s

d = 100 m

Thus;

40² - 10² = 2a(100)

1500 = 200a

a = 1500/200

a = 7.5 m/s²

Read more about sum of integers at; brainly.com/question/17695139

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