A. The data in the table represent a function. y=x/2. This is seen as for every value of x in the table, y=x/2(half of it). You can show this further by trying this fact on each value.
B. For the original function, when x =8, y=x/2=4
For the function given in this part, when x=8, y=3(8)-10
y=24-10 y=14
This means the relation given in this part has a greater value when x=8
C. When x=80, f(x)=3(80)-10
=240-10
=230
Answer:
-5<x>-2
_
Step-by-step explanation:
87/1000 into a decimal is 0.087,
You can divide with your calculator, or you can use place value.
0.8 = 8/10
0.87 = 87/100
0.087 = 87/1000
And so on and so forth...
Answer:
7
Step-by-step explanation:
This is a Poisson distribution problem with the formula;
P(x;μ) = (e^(-μ)) × (μ^(x))/x!
We are told that the grocer sells three of a certain article per week. Thus;
μ = 3
Now, we want to find out How many of these should he have in stock so that the chance of his running out within a week is less than 0.01.
This means;
P(X > k) < 0.01
This can be rewritten as;
P(X ≤ k) < 0.99
Let's try x = 8
P(8;3) = (e^(-3)) × (3^(8))/8!
P(8;3) = 0.008
But; P(X ≤ 8) = 1 - 0.008 = 0.992
This is more than 0.99 and thus is not the answer
Let's try x = 7
P(7;3) = (e^(-3)) × (3^(7))/7!
P(7;3) = 0.022
But; P(X ≤ 7) = 1 - 0.022 = 0.978
Thus is less than 0.99.
Thus, stock should be 7
