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butalik [34]
3 years ago
12

Can someone help me with these questions please ?!!!

Mathematics
1 answer:
k0ka [10]3 years ago
6 0

Answers:

Number 19: 420 / 14 = 30 words per minute

Number 20: im not sure  

Number 21: 14

Number 22: 80 / 2 = 40 boxes.  40 boxes / 10 = 4 candy per box

6 hours x 40 = 240 boxes. 240 x 4 = (960 candy in 6 hours)



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An engineer deposits $2,000 per month for four years at a rate of 24% per year, compounded semi-annually. How much will he be ab
Alex17521 [72]

The amount of money he will be able to withdraw after 10 years after his last deposit is $926,400.

<h3>Compound interest</h3>

  • Principal, P = $2,000 × 12 × 4

= $96,000

  • Time, t = 10 years
  • Interest rate, r = 24% = 0.24
  • Number of periods, n = 2

A = P(1 + r/n)^nt

= $96,000( 1 + 0.24/2)^(2×10)

= 96,000 (1 + 0.12)^20

= 96,000(1.12)^20

= 96,000(9.65)

= $926,400

Therefore, the amount of money he will be able to withdraw after 10 years after his last deposit is $926,400

Learn more about compound interest:

brainly.com/question/24924853

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5 0
2 years ago
A trimming operation at a local manufacturer produces rods whose length conforms to unifrom distribution with a minimum of 18cm
MariettaO [177]

Answer:

The probability that randomly selected road will be at least 25.8 cm long will be 48%.

Step-by-step explanation:

Given: uniform distribution with min and max values of 18 and 33 respectively.

To find : probability density for upper cumulative frequency i.e 25.8 at least means x\geq25.8  upto 33 cm i.e the maximum limit of function.

Solution:

we have by definition , of uniform distribution

we get , probability density function defines as :

<em>F(x,a,b)= </em>\frac{1}{b-a}<em>   </em>a\leq x\leq b

            =1/(33-18)=1/15=0.0667.

this is probability density function.

here the x=25.8 , a=18 and b=33

for lower cumulative frequency it defines as ;

P(x,a,b)=\frac{x-a}{b-a} =25.8-18/33-18=0.52

for upper cumulative frequency it defines as ;

Q(x,a,b)=b-x/b-a=33-25.8/33-18=0.48

here at least 25.8 cm probability means it should be greater than a value(18cm) hence it is provided by the upper cumulative frequency

i.e. Q(x,a,b)=0.48

The probability that randomly selected road will be at least 25.8 cm long will be 48%.

7 0
3 years ago
Which of the following pieces are congruent?
posledela

Answer:

The horizontal segment of E and vertical segments of M.

Step-by-step explanation:

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I think it's a rational number.

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This is the answer ....

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