Question

Let me know the answer plz

Answer 1

Answer:

J. $-\frac{1}{36}$, $\frac{1}{216}$, $-\frac{1}{1296}$

Step-by-step explanation:

We are given the following geometric sequence and we are to find its 8th term:

$-36, 6, -1, \frac{1}{6},...$

Here $a_1=-36$ and common ratio $(r) = \frac{-1}{6}=\frac{-1}{6}$.

The formula we will use to find the next three terms is:

nth term = $a_1 \times r^{(n-1)}$

5th term = $-36 \times \frac{-1}{6}^{(5-1)}$  = $-\frac{1}{36}$

6th term = $-36 \times \frac{-1}{6}^{(6-1)}$  = $\frac{1}{216}$

7th term = $-36 \times \frac{-1}{6}^{(7-1)}$  = $-\frac{1}{1296}$

Answer 2

Answer:

J

Step-by-step explanation:

Find the common ratio r of the geometric sequence then multiply a term by r to obtain the next term

r = $\frac{a_{2} }{a_{1} }$ = $\frac{6}{-36}$ = - $\frac{1}{6}$

The next 3 terms are

$\frac{1}{6}$ × - $\frac{1}{6}$ = - $\frac{1}{36}$

- $\frac{1}{36}$ × - $\frac{1}{6}$ = $\frac{1}{216}$

$\frac{1}{216}$ × - $\frac{1}{6}$ = - $\frac{1}{1296}$