Question

If s(x)= 2-x^2 and t(x)=3×, which value is equivalent to ( s(t(×)) (-7)

Answer 1

Answer:

Step-by-step explanation:

Given that s(x)= 2-x^2 and t(x)=3×

To find which value is equivalent to ( s(t(×)) (-7)

This is composition of functions where t is performed first and then s

x=-7

t(-7)=$3^{-7}$

NOw s(t(-7))=s($3^{-7}$)

=$2-(3^{-7})^{2} =2-\frac{1}{3^{14} }$

simplify to get

1.99999