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2 years ago

What is 20 dg to milligrams

Mathematics

1 answer:

Alla [95]2 years ago

6 0

1 dg = 10 000 milligrams
20 dg = 200 000 milligrams

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A line passes through the point (-7,5) And has a slope of 1/2 which is another point that the line passes through

Licemer1 [7]

(9,13) would be another point that the line passes through.

5 0

3 years ago

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Josh is making 3 recipes one requires 2/3 cups of flour and otherwise 7/8 of a cup of flour in the third requires 3/4 cup of flo

kati45 [8]

Answer:

2 7/24C

Step-by-step explanation:

Start by finding the common denominator. In this case, it's 24. Next, start translation.

2/3C = 16/24C

7/8C = 21/24C

3/4C = 18/24C

Then find the sum.

16/24C + 21/24C + 18/24C = 55/24C = 2 7/24C

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3 years ago

Classify the following triangle

jek_recluse [69]

Acute-The angle is less than 90 degrees

Equilateral-All sides are equal in length

Isosceles-Two of the sides are equal in length

Scalene-None of the sides are equal in length

Right-The angle is 90 degrees

Obtuse-The angle is greater than 90 degrees

We can see that none of the sides are the same length, so we know that it must be scalene. We can also see that every angle is less than 90 degrees, so we know that is must be acute.

The triangle is scalene and acute.

Hope this helps!!

3 0

3 years ago

In ΔABC, m∠B = m∠C. The angle bisector of ∠B meets AC at point H and the angle bisector of ∠C meets AB at point K. Prove that BH

solniwko [45]

Answer:

See explanation

Step-by-step explanation:

In ΔABC, m∠B = m∠C.

BH is angle B bisector, then by definition of angle bisector

∠CBH ≅ ∠HBK

m∠CBH = m∠HBK = 1/2m∠B

CK is angle C bisector, then by definition of angle bisector

∠BCK ≅ ∠KCH

m∠BCK = m∠KCH = 1/2m∠C

Since m∠B = m∠C, then

m∠CBH = m∠HBK = 1/2m∠B = 1/2m∠C = m∠BCK = m∠KCH (*)

Consider triangles CBH and BCK. In these triangles,

∠CBH ≅ ∠BCK (from equality (*));
∠HCB ≅ ∠KBC, because m∠B = m∠C;
BC ≅CB by reflexive property.

So, triangles CBH and BCK are congruent by ASA postulate.

Congruent triangles have congruent corresponding sides, hence

BH ≅ CK.

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2 years ago

45^2 ÷ 78 = ????????

elena55 [62]

$\frac{(45)^2}{78}$

To solve the problem find the value of (45)^2 at first

$(45)^2=2025$ $\frac{2025}{78}=25\text{ R75}$

The answer is 25 with the remainder 75

$25\frac{75}{78}$

You can simplify the fraction to be 25/26

$25\frac{25}{26}$

3 0

1 year ago