(_/18+2_/3)^(2
=(3_/2^(2 + (2)(2_/3)(3_/2) + 2_/3^(2)
=18+ 12_/6 +12
=30+12_/6
hope this helps
=(3_/2^(2 + (2)(2_/3)(3_/2) + 2_/3^(2)
=18+ 12_/6 +12
=30+12_/6
hope this helps
The three circles in the diagram have center ABC true or false
1 answer:
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