5X^4 + 2X^2 – 8
Its quadratic form is 5(x²)² +2x² -8
<span>Let be X²=p, so the final expression is 5p²+2p-8</span>
Given that a polynomial function P(x) has rational coefficients.
Two roots are already given which are i and 7+8i,
Now we have to find two additional roots of P(x)=0
Given roots i and 7+8i are complex roots and we know that complex roots always occur in conjugate pairs so that means conjugate of given roots will also be the roots.
conjugate of a+bi is given by a-bi
So using that logic, conjugate of i is i
also conjugate of 7+8i is 7-8i
Hence final answer for the remaining roots are (-i) and (7-8i).
Answer:
What does it even say? Plus i'm 5th grade sooo, me OUT!
Step-by-step explanation:
This is the answer and the steps