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tamaranim1 [39]

3 years ago

10

(-5, -1, 10, -9) on the number line.

1 answer:

lbvjy [14]3 years ago

4 0

-9,-5, -1, 10 is the right order

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How much money will you have if you started with $30 and put it in an account that earned 11% every year for 5 years?

Elis [28]

At the end of each year, the amount is (1 + 11%) = 1.11 times the amount at the beginning of the year. When that multiplier is applied 5 times, the result is
$30 * 1.11^5 ≈ $50.55

6 0

3 years ago

Chris has 5 1/2cups of water in a pitcher. He pours 3/8 cup of water into a glass. How many cups of water is left in the pitcher

igomit [66]

Answer: The Answer is 5 1/8.

Step-by-step explanation:

6 0

3 years ago

A simple random sample of items resulted in a sample mean of . The population standard deviation is . a. Compute the confidence

Varvara68 [4.7K]

Answer:

(a): The 95% confidence interval is (46.4, 53.6)

(b): The 95% confidence interval is (47.9, 52.1)

(c): Larger sample gives a smaller margin of error.

Step-by-step explanation:

Given

$n = 30$ -- sample size

$\bar x = 50$ -- sample mean

$\sigma = 10$ --- sample standard deviation

Solving (a): The confidence interval of the population mean

Calculate the standard error

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {30}}$

$\sigma_x = \frac{10}{5.478}$

$\sigma_x = 1.825$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.825$

$E = 3.577$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 3.577$

$Lower = 46.423$

$Lower = 46.4$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 3.577$

$Upper = 53.577$

$Upper = 53.6$ --- approximated

<em>So, the 95% confidence interval is (46.4, 53.6)</em>

Solving (b): The confidence interval of the population mean if mean = 90

First, calculate the standard error of the mean

$\sigma_x = \frac{\sigma}{\sqrt n}$

$\sigma_x = \frac{10}{\sqrt {90}}$

$\sigma_x = \frac{10}{9.49}$

$\sigma_x = 1.054$

The 95% confidence interval for the z value is:

$z = 1.960$

Calculate margin of error (E)

$E = z * \sigma_x$

$E = 1.960 * 1.054$

$E = 2.06584$

The confidence bound is:

$Lower = \bar x - E$

$Lower = 50 - 2.06584$

$Lower = 47.93416$

$Lower = 47.9$ --- approximated

$Upper = \bar x + E$

$Upper = 50 + 2.06584$

$Upper = 52.06584$

$Upper = 52.1$ --- approximated

<em>So, the 95% confidence interval is (47.9, 52.1)</em>

Solving (c): Effect of larger sample size on margin of error

In (a), we have:

$n = 30$ $E = 3.577$

In (b), we have:

$n = 90$ $E = 2.06584$

<em>Notice that the margin of error decreases when the sample size increases.</em>

4 0

3 years ago

How do I answer this question?

Nookie1986 [14]

6 = - 4/y
6y = -4
y = -4/6
y = -2/3

7 0

3 years ago

You are offered two different jobs for the month of July, and you decide which one to accept. Your goal is to save as much money

Monica [59]

Answer:

60 hours

Step-by-step explanation:

300 + 5x = 10x

subtract 5x from both sides to cancel 5x on the left

300 = 5x

divide both by 5

60 = x

6 0

3 years ago

Read 2 more answers