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krok68 [10]
4 years ago
5

Identify the center and radius. (x+13)^2 +(y-8)^2 =10

Mathematics
1 answer:
SVEN [57.7K]4 years ago
4 0

Answer:

Center: (−13,8)

Radius: √10

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Help me ! please thamks
Bond [772]

Answer:

The answer will be -13

-15+-13=-28

8 0
4 years ago
By which smallast number must the following number be divided so that the quotient is a perfect cube
jenyasd209 [6]

Answer:

60

Step-by-step explanation:

8640/60 is 144. 144 is a perfect square. 12*12 is 144

8 0
3 years ago
Read 2 more answers
The half-life of a radioactive substance is the time it takes for a quantity of the substance to decay to half of the initial am
posledela

Step-by-step walkthrough:

a.

Well a standard half-life equation looks like this.

N = N_0 * (\frac{1}{2})^{t/p

N_0 is the starting amount of parent element.

N is the end amount of parent element

t is the time elapsed

p is a half-life decay period

We know that the starting amount is 74g, and the period for a half-life is 2.8 days.

Therefore you can create a function based off of the original equation, just sub in the values you already know.

N(t) = 74g * (\frac{1}{2})^{t/2.8days

b.

This is easy now that we have already made the function. Here we just reuse it, but plug in 2.8 days.

N(t) = 74g * (\frac{1}{2})^{t/2.8days} = N(2.8days) = 74g * (\frac{1}{2})^{2.8days/2.8days}\\= 74g * \frac{1}{2}  =  37g

c.

Now we just gotta do some algebra. Use the original function but this time, replace N(t) with 10g and solve algebraically.

10g = 74g * (\frac{1}{2})^{t/2.8days}\\\\\frac{10g}{74g} = (\frac{1}{2})^{t/2.8days}

Take the log of both sides.

log(\frac{5}{37}) = log((\frac{1}{2})^{t/2.8days})

Use the exponent rule for log laws that, log(b^x) = x*log(b)

log(\frac{5}{37}) = \frac{t}{2.8days} * log(\frac{1}{2})

\frac{log(\frac{5}{37})}{log(\frac{1}{2})}  = \frac{t}{2.8days}

2.8 * \frac{log(\frac{5}{37})}{log(\frac{1}{2})}  = t

slap that in your calculator and you get

t = 8.1 days

7 0
2 years ago
A rectangular parking lot is 120 feet long and 75 feet wide. Diego made another scale drawing of the parking lot at a scale of 1
andrew11 [14]

Answer:

We kindly invite you to read carefully the explanation detailed below for further details.

Step-by-step explanation:

At first we understand that Diego converted length and wide units from feet to inches (1\,ft = 12\,in) and then he divided each term by 180, since he was using a reduction scale, so that rectangular parking lot can be represented on paper. That is:

Step 1 - Unit conversion:

l = 120\,ft (l - Length)

l = 120\,ft\times \frac{12\,in}{1\,ft}

l = 1440\,in

w = 75\,ft (w - Width)

w = 75\,ft\times \frac{12\,in}{1\,ft}

w = 900\,in

Step 2 - Applying scaling:

l' = \frac{l}{180} (l' - Scaled length)

l' = \frac{1440\,in}{180}

l' = 8\,in

w' = \frac{w}{180} (w' - Scaled width)

w' = \frac{900\,in}{180}

w' = 5\,in

6 0
4 years ago
40 POINTS answer correctly
Alexxx [7]
Since the denominator is the number on the bottom, we need to find a common denominator for a and 5a^2. Since a*5a is 5a^2, we have a common denominator - 5a^2! For the fractions, that means that since a*5a=5a^2, we have to multiply -7 by 5a to get -35a/5a^2-9/5a^2=(-35a-9)/5a^2
7 0
3 years ago
Read 2 more answers
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