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3 years ago

How to slove -6≤17+p

Mathematics

1 answer:

goblinko [34]3 years ago

6 0

Hello there!

Answer: ⇒⇒⇒⇒⇒ $p\geq-23$

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Step-by-step explanation:

First you had to switch sides.

$17+p\geq-6$

Then you subtract by 17 from both sides of equation.

$17+p-17\geq-6-17$

Simplify it should be the correct answer.

$p\geq-23$

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Hope this helps!

Thank you for posting your question at here on brainly.

Have a great day!

-Charlie

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Question 5^ Need help ... ASAP ... your help is really appreciated ...

goblinko [34]

Answer:

See below

Step-by-step explanation:

I think we had a question similar to this before. Again, let's figure out the vertical and horizontal distances figured out. The distance from C at x=8 to D at x=-5 is 13 units while the distance from C at y=-2 to D at y=9 is 11 units. (8+5=13 and 2+9=11, even though some numbers are negative, we're looking at their value in those calculations)

Next, we have to divide each distance by 4 so we can apply it to the ratio. 13/4= $\frac{13}{4}$ and 11/4= $\frac{11}{4}$ . Next, we need to read the question carefully. It's asking us to place the point in the ratio 3 to 1 from C to D. The point has to be closer to endpoint D because of this. Let's take each of our fractions, multiply them by 3, then add them towards the direction of endpoint D to get our answer (sorry if that sounds confusing):

$\frac{13}{4}*3 = \frac{39}{4}\\ 8-\frac{39}{4} = \frac{-7}{4}\\\frac{11}{4}*3 = \frac{33}{4} \\-2+\frac{33}{4} = \frac{25}{4}$

Therefore, our point that partitions CD into a 3:1 ratio is ( $\frac{-7}{4}, \frac{25}{4}$ ).

I'm not sure if there was more to #5 judging by how part B was cut off. From what I can understand of part B, however, I believe that Beatriz started from endpoint D and moved towards C, the wrong direction. She found the coordinates for a 1:3 ratio point.

Also, for #6, since a square is a 2-dimensional object, the answer needs to be written showing that. The answer for #6 is 9 units^2.

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Examples : A number of shapes like squares, circles, regular hexagon, etc. have rotational symmetry.

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SashulF [63]

Answer:

Step-by-step explanation:

Here's a step by step tutorial on your calculator on how to do this.

Hit "stat" then "1: Edit". If there are numbers there, arrow up to highlight L1, or L2, or wherever there are numbers. Hit "clear" then "enter" and the numbers will be gone. In L1, enter the Practice throws values. Press 3 then enter, then 12 then enter, then 6 then enter, etc. til all of them are in L1's column. Then arrow over to L2 and do the same with entering all the Free Throw values.

When you're done, hit "stat" again, then arrow over once to "calc" and #4 should say LinReg. That's a linear regression equation. If you have a TI 83, just hit enter and you'll get the equation in the form y = mx + b. If you have a TI 84 or 84+, you'll need to arrow down to the word "calculate" and then you'll see the equation.

One thing...if you have not turned your diagnostics on, you wont be able to see the coefficient of determination (the r-squared value). To make sure it's on:

Hit 2nd, then 0. You have opened up the catalog which lists every single thing your calculator can do in alphabetical order. The hit the button UNDER the MATH button (x to the negative 1) and scroll down until you see "diagnosticsON" and hit enter twice.

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y = 2.352x - .852 with an r-squared value of .844

To get the quadratic regression equation, hit "stat" then "calc" then choose #5, QuadReg. Repeat the process to calculate your equation. Mine was

$y=.073x^2+1.205x+2.555; r^2=.855$

And for the exponential regression, choose ExpReg (mine is under 0. Yours may be some other number. Just arrow down til you find it, it's there!) My ExpReg equation was

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It appears that the r-squared value is the highest in the quadratic regression equation, so that's the best fit.

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