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3 years ago

Rob pays $258 every 3 months for his karate lessons. At this rate, how much will Rob pay for 3 years of karate lessons?

2 answers:

6 0

Well first divide 3 years into months and there are 36 months in 3 years, next divide 258 into 3 months and that is 86, next multiply 86 by 36 and you get 3,096

Steps:
3 Years into months is 36
258 Divided by 3 is 86
86 Times 36 is 3,096

Answer $3,096

GREYUIT [131]3 years ago

6 0

If he pays 258 every three month it means that he pays 1034(258x4) every year. Therefore in 3 years he will pay 1034 multiplied by three which is 3096

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In the picture below, ABCD is a rectangle. If the area of triangle ABE is 40, what is the area of the triangle?

MariettaO [177]

Area of the rectangle: 112

Step-by-step explanation:

Picture is missing: find it in attachment.

The area of a triangle is given by

$A=\frac{1}{2}bh$

where

b is the length of the base

h is the height

For triangle ABE, we know that

A = 40 (area)

h = 8 (height)

So we can find the length of the base AE:

$AE=b=\frac{2A}{h}=\frac{2(40)}{8}=10$

Now we observe that the base of the rectangle, AD, is the sum of AE and DE, therefore:

$AD=AE+DE=10+4=14$

We also know the height of the rectangle AB is 8, and that the area of a rectangle is

$A=bh$

where b is the base and h the height. Therefore, the area of this rectangle is

$A=bh=(AD)(AB)=(14)(8)=112$

Learn more about area of figures:

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7 0

4 years ago

You have learned that different types of rocks are found in Earth’s layers. Their composition affects their densities.

gtnhenbr [62]

Answer:

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Step-by-step explanation:

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6 0

3 years ago

Read 2 more answers

CAN SOMEONE PLEASE HELP ME ASAP PLEASEEEE!!!

Rom4ik [11]

Answer:

11.4

Step-by-step explanation:

So we know that Triangle ACB is similar to Triangle EFD.

This means that their sides are proportional to each other.

We want to find x or side AB. To do so, we can set up a proportion.

The proportional side to AB is ED. Let's also use BC since we know its value. The proportional side to BC is DF. Thus:

$\frac{AB}{ED}=\frac{BC}{DF}$

Substitute x for AB, 3.8 for Ed, 15 for BC, and 5 for DF. Thus:

$\frac{x}{3.8}=\frac{15}{5}$

Reduce the right:

$\frac{x}{3.8}=\frac{3}{1}$

Cross multiply:

$x=11.4$

So, the value of x is 11.4

And we're done!

7 0

3 years ago

Find the equation of locus of a point which moves such that its distance from (0,2) is one third distance from (-2,3). ( I WILL

scoray [572]

Answer:

$8(x^2+y^2)-4x-30y+23=0$

Step-by-step explanation:

<u />

<u>Distance formula</u>

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Let P(x, y) = any point on the locus

Let A = (0, 2)

Let B = (-2, 3)

If a point moves such that its distance from (0, 2) is one third distance from (-2, 3):

$PA=\dfrac{1}{3}PB$

Therefore, using the distance formula:

$\implies \sqrt{(x-0)^2+(y-2)^2}=\dfrac{1}{3}\sqrt{(x-(-2))^2+(y-3)^2}$

Square both sides:

$\implies x^2+(y-2)^2=\dfrac{1}{9}[(x+2)^2+(y-3)^2]$

$\implies x^2+y^2-4y+4=\dfrac{1}{9}(x^2+4x+4+y^2-6y+9)$

Multiply both sides by 9:

$\implies 9x^2+9y^2-36y+36=x^2+4x+4+y^2-6y+9$

$\implies 8x^2+8y^2-4x-30y+23=0$

$\implies 8(x^2+y^2)-4x-30y+23=0$

3 0

2 years ago

Solve for x, x^2-3x-5=0

Sophie [7]

Okay so for this one, we have to isolate our X.Lets start by moving the negative 5 on the other side of the equal sign. Remember to not mix a number that is with an X with a normal number (in this case it would be the -3x and the -5). So in putting our -5 on the other sign it becomes positive. Here’s what we have: x^2-3x=5. x^2 is the same thing as 2x.So now you have to minus 3x off of your 2x. This gives us -1x, but can just be put as -x. So now we have -x=5. You’re answer could either be 5 or -5 if you decided to divide it by -1 seeing as your -x is technically -1.

7 0

3 years ago