Given that the graph shows tha the functión at x = 0 is below the y-axis, the constant term of the function has to be negative. This leaves us two possibilities:
y = 8x^2 + 2x - 5 and y = 2x^2 + 8x - 5
To try to discard one of them, let us use the vertex, which is at x = -2.
With y = 8x^2 + 2x - 5, you get y = 8(-2)^2 + 2(-2) - 5 = 32 - 4 - 5 = 23 , which is not the y-coordinate of the vertex of the curve of the graph.
Test the other equation, y = 2x^2 + 8x - 5 = 2(-2)^2 + 8(-2) - 5 = 8 - 16 - 5 = -13, which is exactly the y-coordinate of the function graphed.
Then, the answer is 2x^2 + 8x -5
D how much randall occured in january?
Answer:
The function is odd.
Step-by-step explanation:
A function is even if the graph of the function is symmetric with respect to the y-axis. A function is odd if the graph of the function is symmetric with respect to the origin. To find if the function is even or odd, we're going to graph the function using DESMOS.
As you can see in the attached picture, the function is symmetric with respect to the origin. Therefore, the function is odd.
Hello!
The answer to your question is D. 17.83 because 41 divided by 2.3 is equal to the answer and you are trying to solve for r.
