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4 years ago

The base of a triangle is four times its height.If the area of the triangle is 242 square millimeters,find its height

Mathematics

1 answer:

makkiz [27]4 years ago

6 0

Http://www.clayton.k12.mo.us/cms/lib/MO01000419/Centricity/Domain/892/area%20of%20parallelograms%20a...

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What is the 15th term of the sequence A(n) = -3n+50 ?

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3 years ago

The air temperature in the North Pole in the morning was 3 degrees Celsius. By 10:00 am the temperature dropped 12 degrees. By n

WINSTONCH [101]

Answer: -11 degrees Celsius

Step-by-step explanation:

First you subtract 3-12 leaving -9 then you add positive 5 to -9 giving you -4 then add 9 to equal 5 and lastly 5- 16 to get -11.

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3 years ago

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4 years ago

Roberta jogs 3 laps the first day, 5 laps the second day, 7 laps the third, and so on. On which day will Roberta jog 13 laps if

-BARSIC- [3]

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3 years ago

What is quartile 1 (Q1)quartile 3 (Q3) and the IQR? Answer all three parts . 13, 23, 24, 25, 26, 26, 37, 47, 47, 48, 50

Fittoniya [83]

Answer:

Quartile 1 (Q1) = 24

Quartile 2 (Q2) = 47

IQR = 23

Step-by-step explanation:

Given:

The set of data are:

13, 23, 24, 25, 26, 26, 37, 47, 47, 48, 50

The data are in increasing order. The number terms are, $n = 11$ .

Therefore, the middle term = $\frac{n+1}{2}=\frac{11+1}{2}=6^{th}\ term$

So, the median = 26

Now, the median divides the set of data into two parts. The median of first part is the quartile 1 and the median of second part is quartile 2.

So, the first part has the following terms:

13, 23, 24, 25, 26

Here also, $n=5$ . So, the third term is the median.

∴ Q1 = 24

The second part has the following terms:

37, 47, 47, 48, 50

Here also, $n=5$ . So, the third term is the median.

∴ Q2 = 47.

Now, IQR = Q2 - Q1 = 47 - 24 = 23.

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4 years ago