Can anybody help me with this problem?
2 answers:
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Answer:
The function is y = 2x + 1.
And mike graphed the function correctly.
Menna took the point where the function touches x-axis incorrectly.
Instead of (-1/2,0), Menna took it as (-2,0)
Step-by-step explanation:
The equation y = mx +c indicates a straight line whose slope is m
And y-intercept is c.
y-intercept is nothing but the distance between origin and point where the graph crosses the y-axis (0,c).
Now, this graph crosses x-axis when y = 0.
⇒ mx + c = 0; ⇒ x = .
Now, by comparing y = 2x + 1 with y = mx + c.
m=2 and c=1
⇒ the graph should crosses y-axis at (0,c) = (0,1)
And touch x-axis at ( , 0) = (
,0)
⇒ mike graphed the function correctly.
Menna took the point where the function touches x-axis incorrectly.
Instead of (-1/2,0), Menna took it as (-2,0)