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3 years ago

10. In a warehouse, the workers sometimes slide boxes along the floor to move them. Two boxes

Mathematics

1 answer:

RSB [31]3 years ago

7 0

Answer:

The Box 1 and Box 2 are the same mass.

Explanation:

It caused both to change speed because they have both the same mass.

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Please help, show all steps, thank u!

Viktor [21]

The percent increased

4 0

3 years ago

Read 2 more answers

A, B and C form a triangle where ∠BAC = 90°

Stells [14]

Answer:

14.1 mm

Given:

∠BAC = 90° (angle A should be 90°)

AB = 4.4mm

BC = 14.8mm

See the diagram given below.

<u>Solving using Pythagoras Theorem</u>: a² + b² = c²

x² + 4.4² = 14.8²

x = 14.8² - 4.4²

x = 219.04 - 19.36

x = 199.68

x = √199.68

x = 14.13 ≈ 14.1 mm (rounded to 1 decimal place)

7 0

2 years ago

Read 2 more answers

Without using a calculator, order the following expressions from least to greatest.

LekaFEV [45]

Answer:

$\displaystyle \large{\frac{11}{3} < \sqrt{17} < \sqrt{20}}$

Step-by-step explanation:

( 1 ) 11/3

$\displaystyle \large{\frac{11}{3}}$ can be converted to mixed fractions to $\displaystyle \large{3\frac{2}{3}}$

Therefore, 11/3 is at least around 3, almost 4. It could be more than 3.5 by approximation but not exactly 4.

( 2 ) √20

$\displaystyle \large{\sqrt{20}=\sqrt{5\cdot 4}}\\\displaystyle \large{\sqrt{20}=\sqrt{5\cdot 2\cdot 2}}\\\displaystyle \large{\sqrt{20}=2\sqrt{5}}$

We know that $\displaystyle \large{\sqrt{4}=2}$ so $\displaystyle \large{\sqrt{5} > \sqrt{4}}$ which means approximately, $\displaystyle \large{\sqrt{20}}$ can be either at least 4.3 up to 4.4

( 3 ) √17

We know that $\displaystyle \large{\sqrt{16} = 4}$ so $\displaystyle \large{\sqrt{17}}$ can be at least 4.1 up to 4.2, but it’s obvious that the square root of 17 is less than square root of 20 since $\displaystyle \large{\sqrt{a} > \sqrt{b}}$ for a > b