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Karo-lina-s [1.5K]
3 years ago
11

Menţionează rolul virgulei în secvența: — Ei, ce ziceți?.

Mathematics
1 answer:
vodka [1.7K]3 years ago
6 0

Answer:

The given question is:

<em>"Mention the role of the comma in the sequence: - Well, what do you say?"</em>

<em />

The role of the comma is to indicate a separation between words to make a specific sense of the statement.

Actually, the official function of commas is to separate words, ideas, phrases to prevent a misreading, and to give a specific signification so readers won't capture the intended sense.

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Lelu [443]

Answer:

hi

Step-by-step explanation:

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3 years ago
Read 2 more answers
By how much is the product of 9/5 and 8 1/4 greater than 5
Oliga [24]

Given:

The product of \dfrac{9}{5} and 8\dfrac{1}{4} greater than 5.

To find:

By how much the product of \dfrac{9}{5} and 8\dfrac{1}{4} greater than 5.

Solution:

First we need to find the product of \dfrac{9}{5} and 8\dfrac{1}{4}.

\text{Product}=\dfrac{9}{5}\times 8\dfrac{1}{4}

\text{Product}=\dfrac{9}{5}\times \dfrac{8(4)+1}{4}

\text{Product}=\dfrac{9}{5}\times \dfrac{33}{4}

\text{Product}=14.85

Now subtract 5 from the product.

14.85-5=9.85

Therefore, the product of \dfrac{9}{5} and 8\dfrac{1}{4} is 9.85 greater than 5.

3 0
2 years ago
Why is 1 + (−5) equal to −4? (1 point)
Dafna11 [192]

I'm pretty sure it's D

Filler to post

7 0
3 years ago
Read 2 more answers
2ᵃ = 5ᵇ = 10ⁿ.<br> Show that n = <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bab%7D%7Ba%20%2B%20b%7D%20" id="TexFormula1" titl
11Alexandr11 [23.1K]
There are two ways you can go about this: I'll explain both ways.
<span>
</span><span>Solution 1: Using logarithmic properties
</span>The first way is to use logarithmic properties.

We can take the natural logarithm to all three terms to utilise our exponents.

Hence, ln2ᵃ = ln5ᵇ = ln10ⁿ becomes:
aln2 = bln5 = nln10.

What's so neat about ln10 is that it's ln(5·2).
Using our logarithmic rule (log(ab) = log(a) + log(b),
we can rewrite it as aln2 = bln5 = n(ln2 + ln5)

Since it's equal (given to us), we can let it all equal to another variable "c".

So, c = aln2 = bln5 = n(ln2 + ln5) and the reason why we do this, is so that we may find ln2 and ln5 respectively.

c = aln2; ln2 = \frac{c}{a}
c = bln5; ln5 = \frac{c}{b}

Hence, c = n(ln2 + ln5) = n(\frac{c}{a} + \frac{c}{b})
Factorise c outside on the right hand side.

c = cn(\frac{1}{a} + \frac{1}{b})
1 = n(\frac{1}{a} + \frac{1}{b})
\frac{1}{n} = \frac{1}{a} + \frac{1}{b}

\frac{1}{n} = \frac{a + b}{ab}
and thus, n = \frac{ab}{a + b}

<span>Solution 2: Using exponent rules
</span>In this solution, we'll be taking advantage of exponents.

So, let c = 2ᵃ = 5ᵇ = 10ⁿ
Since c = 2ᵃ, 2 = \sqrt[a]{c} = c^{\frac{1}{a}}

Then, 5 = c^{\frac{1}{b}}
and 10 = c^{\frac{1}{n}}

But, 10 = 5·2, so 10 = c^{\frac{1}{b}}·c^{\frac{1}{a}}
∴ c^{\frac{1}{n}} = c^{\frac{1}{b}}·c^{\frac{1}{a}}

\frac{1}{n} = \frac{1}{a} + \frac{1}{b}
and n = \frac{ab}{a + b}
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Rihanna has a mixture of nickels and quarters in her piggy
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22 quarters and 4 nickels
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