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2 years ago

Find the value of x. 8. x+9 2x

Mathematics

1 answer:

just olya [345]2 years ago

3 0

$2x = \frac{x+2}{2} => 4x = x + 2 => 3x = 2 => x = 2/3$

ok done. Thank to me :>

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spin [16.1K]

The answers are A. and B.

Step-by-step explanation: I just took the test and it was right ; )

4 0

4 years ago

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Solve x2 - 8x - 9 = 0. Rewrite the equation so that it is of the form x2 + bx = c.

barxatty [35]

Answer:

x=9,-1 and $x^2+(-8)x=9$

Explanation:

we have been given with the quadratic equation $x^2-8x-9$

we compare the given quadratic equation with general quadratic equation

general quadratic is $ax^2+bx+c=0$

from given quadratic equation a=1,b= -8,c= -9

substituting these values in the formula for discriminant $D=b^{2}-4ac$

$D=(-8)^2-4(1)(-9)=100$

Now, to find the value of x

Formula is $x=\frac{-b\pm\sqrt{D}}{2a}$

Now, substituting the values we will get

$x=\frac{-(-8)\pm\sqrt{100}} {2}= \frac{8\pm10}{2}=9,-1$

And rewritting the given equation by shifting 9 to right hand side of the given equation and taking minus inside the bracket so as to convert it in the form of

$x^2+bx=c$

4 0

3 years ago

Read 2 more answers

What second degree polynomial function has a leading coefficient of -2 and root 4 with a multiplicity of 2

OverLord2011 [107]

The second degree polynomial with leading coefficient of -2 and root 4 with multiplicity of 2 is:

$p(x) = -2*(x - 4)*(x - 4) = -2*(x - 4)^2$

<h3>How to write the polynomial?</h3>

A polynomial of degree N, with the N roots {x₁, ..., xₙ} and a leading coefficient a is written as:

$p(x) = a*(x - x_1)*(x - x_2)*...*(x - x_n)$

Here we know that the degree is 2, the only root is 4 (with a multiplicity of 2, this is equivalent to say that we have two roots at x = 4) and a leading coefficient equal to -2.

Then this polynomial is equal to:

$p(x) = -2*(x - 4)*(x - 4) = -2*(x - 4)^2$

If you want to learn more about polynomials:

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8 0

2 years ago

HELP DUE IN 15 MINS!

boyakko [2]

Answer:

r = $2\sqrt{5}$