Answer:
Option C: 41
Step-by-step explanation:
<ABD+<CBD=90
<ABD=8x+1
<CBD=6x+5
(8x+1)+(6x+5)=90
Combine like terms
(8x+6x)+(1+5)=90
14x+6=90
14x=90-6
14x=84
divide both sides by 14
x=6
Now we plug that value into <DBC = 6x+5
6(6)+5=
36+5
41
Answer:
Each Pencil Cost 4 Dollars
Step-by-step explanation:
First you can subtract 21 by 9 to get 12 dollars which shows how much he spent.
Second you can divide 12 by 3 to get 4 dollars spent. So he spent 4 dollars on each pencil.
55x5 - 40x5
The third one down
The solution of this equation is x = 5 and x = 9.
<h3>What is the solution?</h3>
Let us recall that what we have here is a radical equation as follows;
√7x+1 - √x-5 = 6
When we isolate we have';
√7x+1 = √x-5+6
Taking the square of both sides;
(√7x+1)^2 = (√x-5+6)^2
Hence;
7x+1 = x-5+36+12√x-5
-12√x-5 = -7x-1+x-5+36
12√x-5 = 6x-30
Raising this equation to power 2
144x-720 = 36x^2-360x+900
When we rearrange we obtain;
36x2 - 504x + 1620 = 0
Hence;
x = 5 and x = 9
Learn more about radical equation:brainly.com/question/8606917
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(9^x) - 3 = 2*3^x
(9^x) - 3 - (2*3^x) = (2*3^x) - (2*3^x)
(9^x) - (2*3^x) - 3 = 0
(3^2)^x - 2*(3^x) - 3 = 0
3^(2x) - 2*(3^x) - 3 = 0
3^(x*2) - 2*(3^x) - 3 = 0
(3^x)^2 - 2*(3^x) - 3 = 0
z^2 - 2*z - 3 = 0 ............ let z = 3^x
(z - 3)(z + 1) = 0
If z-3 = 0, then z = 3 when we isolate z
If z = 3, and z = 3^x, then
z = 3
3^x = 3
3^x = 3^1
x = 1
which is a solutin in terms of x
If z+1 = 0 then z = -1
If z = -1 and z = 3^x, then there are NO solutions for this part of the equation
The quantity 3^x is never negative no matter what the x value is
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Answer: x = 1
